MySQL初学笔记（第一次作业）

查询locations表中，所有的country_id（去重）

select DISTINCT country_id from locations;

选择员工姓名的第三个字母是a的员工姓名和年薪

select last_name,salary*12 as 年薪
from employees
where last_name LIKE '__a%';

查询employees表中，雇用时间在2004-02-06~2014-03-05之间的员工姓名与工号

select last_name,employee_id
from employees
where hiredate BETWEEN '2004-02-06' AND '2014-03-05';

扩展题：将上题条件改为在2004~2014之间

select last_name,employee_id
from employees
where year(hiredate) BETWEEN '2004' and '2014'

查询locations表中，城市不在Roma、Tokyo、Seattle的城市和街道地址信息，要求为城市起对应的中文别名

select city as 城市,street_address
from locations
where city not in('Roma','Tokyo','Seattle')

选择公司中没有管理者的员工姓名及job_id

select last_name,job_id
from employees
where manager_id is null

显示出表employees表中first_name以’e’结尾的员工信息

select *
from employees
where first_name like '%e'

来源：oschina

链接：https://my.oschina.net/u/4303145/blog/4674673