Include JUST files in scandir array?

こ雲淡風輕ζ 提交于 2019-11-27 21:17:00

You can use array_filter.

$indir = array_filter(scandir('../pages'), function($item) {
    return !is_dir('../pages/' . $item);
});

Note this filters out all directories and leaves only files and symlinks. If you really want to only exclude only files (and directories) starting with ., then you could do something like:

$indir = array_filter(scandir('../pages'), function($item) {
    return $item[0] !== '.';
});

Fastest way to remove dots as files in scandir

$files = array_slice(scandir('/path/to/directory/'), 2); 

From the PHP Manual

array_diff will do what you're looking for:

$indir = scandir('../pages');
$fileextensions = array(".", "php", "html", "htm", "shtml");
$indir = array_diff($indir, array('.', '..'));
$replaceextensions = str_replace($fileextensions, "", $indir);

http://php.net/manual/en/function.array-diff.php

I am aware erknrio provided an answer for this, but here is a cleaner way of getting an array of files without directories (modified to be more efficient):

$dirPath = 'dashboard';

$dir = scandir($dirPath);

foreach($dir as $index => &$item)
{
    if(is_dir($dirPath. '/' . $item))
    {
        unset($dir[$index]);
    }
}

$dir = array_values($dir);

You can use this snippet. It returns just files in directory:

function only_files($dir_element) {
    if (!is_dir($dir_element)) {
        return $dir_element;
    }
}

function givemefiles($dir) {
    $scanned_dir = scandir($dir);
    return array_filter($scanned_dir, "only_files");
}

$dir_path = '../pages';

givemefiles($dir_path);
echo "<pre>";
var_dump($scanned_dir);
echo "</pre>";

simply use preg_replace to remove all kind of hidden's file from directory

$files = array(".", "..", "html", ".~html", "shtml");    
$newfiles = preg_grep('/^([^.])/', scandir($files));
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