问题
On my website, I have a table movies
and a table users
I'm trying to have an "Add to favs" button that a user can click, which will add that movie to his favorites (ajax / javascript not necessary at the moment, just php).
So what's the simplest way I could do something like that? I've thought about this but I can't seem to find a solution (all I think of is way too complicated, and in my opinion not possible).
What's your thoughts?
I don't need a ready-made script, just an idea that could get me working (although if you have an example of such script, I'd be happy to look at it).
Thanks!
回答1:
Add a third table:
CREATE TABLE user_favorites (
user_id INT NOT NULL,
movie_id INT NOT NULL,
PRIMARY KEY (user_id, movie_id),
FOREIGN KEY user_id REFERENCES users (user_id),
FOREIGN KEY movie_id REFERENCES movies (movie_id)
)
This is called an intersection table or join table, as it joins rows in the users
table to rows in the movies
table (as you see, each column is a foreign key). It is also defines a many-to-many relationship, because one user can like many movies and one movie can be liked by many users.
When you go to add a favorite movie for a user, all you have to do is insert a row in this table with the ID of the user and the ID of the movie:
INSERT INTO user_favorites(user_id, movie_id) VALUES([user ID], [movie ID])
To see what movies a user has favorited:
SELECT movie_id FROM user_favorites WHERE user_id = [user ID]
回答2:
This is a many-to-many relationship. A user can favorite many movies, and a movie can be favored by many users. In an RDBMS, you represent a many-to-many relationship with a third table. I call this an intersection table but it goes by other names too.
Create a table with two columns. The columns are both foreign keys, referencing movies and users, respectively.
CREATE TABLE Favorites (
user_id INT NOT NULL,
movie_id INT NOT NULL,
PRIMARY KEY (user_id, movie_id),
FOREIGN KEY (user_id) REFERENCES Users(user_id),
FOREIGN KEY (movie_id) REFERENCES Movies(movie_id)
);
When a user chooses to favorite a movie:
INSERT INTO Favorites (user_id, movie_id) VALUES (?, ?)
When a user decides they don't like a movie any longer, delete the corresponding row:
DELETE FROM Favorites WHERE (user_id, movie_id) = (?, ?)
To get the set of movies favored by a given user:
SELECT movie_id FROM Favorites WHERE user_id = ?
To get the set of users who favor a given movie:
SELECT user_id FROM Favorites WHERE movie_id = ?
Regarding one of your comments:
You shouldn't make the "Add to favorite" a link. Indexers like Google will follow links, and then before you know it, every user has favorited every movie.
The general best practice is that read-only operations can be GET requests, while operations that write to the database can be POST requests. This means that you need to use a <form>
element to submit POST requests, not an <a href="...">
element.
回答3:
You will need to create a new table:
user_favorite_movies
--------------------
ID (primary key)
userID (foreign key)
movieID (foreign key)
date
Then when the user clicks the 'Add Favorite' button, you just insert a new row into user_favorite_movies with the users ID from the user table, the movie id from the movie table, and the date it was added (good for sorting later).
Hope this helps!
Best,
-Eric
回答4:
You could create a table favourites
with three columns, id
, mid
and uid
. To add a favourite:
INSERT INTO favourites (mid, uid) VALUES (3, 5)
To search for favourites of one user:
SELECT * FROM favourites WHERE uid = 7
To search for people who favourited one movie:
SELECT * FROM favourites WHERE mid = 9
回答5:
So far as I can see, you'll still need to use JavaScript or Ajax to do the post, unless you want to refresh the page every time thet mark/unmark a favorite, and also to add/remove the new favorite indicator in place at the same time.
Or am I missing something?
来源:https://stackoverflow.com/questions/3722242/system-for-keeping-track-of-user-favorites