How to cut the last field from a shell string

问题

How to cut the last field in this shell string

LINE="/string/to/cut.txt"

So that the string would look like this

LINE="/string/to/"

Thanks in advance!

回答1:

I think you could use the "dirname" command. It takes in input a file path, removes the filename part and returns the path. For example:

$ dirname "/string/to/cut.txt"
/string/to

回答2:

For what it's worth, a cut-based solution:

NEW_LINE="`echo "$LINE" | rev | cut -d/ -f2- | rev`/"

回答3:

This will work in modern Bourne versions such as Dash, BusyBox ash, etc., as well as descendents such as Bash, Korn shell and Z shell.

LINE="/string/to/cut.txt"
LINE=${LINE%/*}

or to keep the final slash:

LINE=${LINE%/*}/

回答4:

echo "/string/to/cut.txt" | awk -F'/' '{for (i=1; i<NF; i++) printf("%s/", $i)}'

回答5:

echo $LINE | grep -o '.*/' works too.

来源：https://stackoverflow.com/questions/4563060/how-to-cut-the-last-field-from-a-shell-string