问题
I would like a third column "items" with the values that are grouped.
var dic = new Dictionary<string, int>();
dic.Add("a", 1);
dic.Add("b", 1);
dic.Add("c", 2);
dic.Add("d", 3);
var dCounts =
(from i in dic
group i by i.Value into g
select new { g.Key, count = g.Count()});
var a = dCounts.Where(c => c.count>1 );
dCounts.Dump();
a.Dump();
This code results in:
Key Count
1 2
2 1
3 1
I would like these results:
Key Count Items
1 2 a, b
2 1 c
3 1 d
回答1:
var dCounts =
(from i in dic
group i by i.Value into g
select new { g.Key, count = g.Count(), Items = string.Join(",", g.Select(kvp => kvp.Key)) });
Use string.Join(",", {array})
, passing in your array of keys.
回答2:
You can use:
var dCounts =
from i in dic
group i by i.Value into g
select new { g.Key, Count = g.Count(), Values = g };
The result created by grouping (value g
) has a property Key
that gives you the key, but it also implements IEnumerable<T>
that allows you to access individual values in the group. If you return just g
then you can iterate over all values using foreach
or process them using LINQ.
Here is a simple dump function to demonstrate this:
foreach(var el in dCounts) {
Console.Write(" - {0}, count: {1}, values:", el.Key, el.Count);
foreach(var item in el.Values) Console.Write("{0}, ", item);
|
回答3:
from i in dic
group i.Key by i.Value into g
select new
{
g.Key,
count = g.Count(),
items = string.Join(",", g.ToArray())
});
来源:https://stackoverflow.com/questions/3239552/get-grouped-comma-separated-values-with-linq