How to annotate a generator in python3?

问题

Python 3.x supports (optional) function annotations:

def add_ints(x:int, y:int) -> int :
    return x+y

I sometimes encounter problems as to how to represent a given "type" can be represented, and this time, I have a function that returns a generator:

def myfunc(x: [int]) -> "generator that returns ints":
    #                     ^~~~~~~~~~~~~~~~~~~~~~~~~~
    return (n for n in x if n%2 == 0)

How should I annotate the return value? Is there any reference I can consult to?

回答1:

The typing module defines the Generator type, which you can use like:

Generator[yield_type, send_type, return_type] 

See also PEP 0484.

回答2:

While Generator[x, y, z] exists, most of the time, you might want to use the less verbose Iterator:

def add_ints(x:int, y:int) -> Iterator[int]:
    return (n for n in x if n%2 == 0)

回答3:

Annotations in Python 3 can be any valid expression, not just a type, and are not actually used for anything internally (for more on annotations, https://www.python.org/dev/peps/pep-3107). There are no guidelines or standards as to how to use these annotations so they can be used in whatever way is easiest for the coder (See https://www.python.org/dev/peps/pep-0008#programming-recommendations).

In your specific case you could use a string or global variable to indicate your type, or perhaps the types.GeneratorType, although there is no way to indicate that the generator produces ints.

来源：https://stackoverflow.com/questions/27264250/how-to-annotate-a-generator-in-python3