问题
I have some data with the following format:
28/04/2017 00:00:00|20550|22/05/2017 00:00:00|
I am setting | as a separator. For the data in the first and third row in this example, I put timestamp as a data type in HUE, but I get nulls as answer.
I have looked around and it seems to me like Hive supports Unix format timestamp (from places like this )
But, I get a "Invalid date" message (I'm doing it with HUE so far, I'm still new with this technologies). If I try to make this data String, I can see values, but when I try to use to_date() the problem persists.
Is there anything I'm ignoring?
回答1:
The only supported timestamp format is yyyy-MM-dd HH:mm:ss with optional fraction of seconds.
Anything else should be read as string and converted later.
Demo
with t as (select '28/04/2017 00:00:00' as mydate)
select from_unixtime(to_unix_timestamp (mydate,'dd/MM/yyyy HH:mm:ss'))
from t
2017-04-28 00:00:00
来源：https://stackoverflow.com/questions/44705050/hive-timestamp-format