How to determine if a string “ends with” another string in R?

别说谁变了你拦得住时间么 提交于 2020-07-18 04:12:07

问题


I want to filter out the rows of a table which contain '*' in the string value of the column. Checking just that column.

 string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")

 zz <- sapply(tx$variant_full_name, function(x) {substrRight(x, -1) =="*"})
 Error in FUN(c("Agno I30N", "VP2 E17Q", "VP2 I204*", "VP3 I85F", "VP1 K73R",  : 
   could not find function "substrRight"

The 4th value of zz should be TRUE by this.

in python there is endswith function for strings [ string_s.endswith('*') ] Is there something similar to that in R ?

Also, is it problem because of '*' as a character as it means any character ? grepl also not working.

> grepl("*^",'dddd*')
[1] TRUE
> grepl("*^",'dddd')
[1] TRUE

回答1:


* is a quantifier in regular expressions. It tells the regular expression engine to attempt to match the preceding token "zero or more times". To match a literal, you need to precede it with two backslashes or place inside of a character class [*]. To check if the string ends with a specific pattern, use the end of string $ anchor.

> grepl('\\*$', c('aaaaa', 'bbbbb', 'ccccc', 'dddd*', 'eee*eee'))
# [1] FALSE FALSE FALSE  TRUE FALSE

You can simply do this without implementing a regular expression in base R:

> x <- c('aaaaa', 'bbbbb', 'ccccc', 'dddd*', 'eee*eee')
> substr(x, nchar(x)-1+1, nchar(x)) == '*'
# [1] FALSE FALSE FALSE  TRUE FALSE



回答2:


This is simple enough that you don't need regular expressions.

> string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
> substring(string_name, nchar(string_name)) == "*"
[1] FALSE FALSE FALSE  TRUE FALSE



回答3:


I use something like this:

strEndsWith <- function(haystack, needle)
{
  hl <- nchar(haystack)
  nl <- nchar(needle)
  if(nl>hl)
  {
    return(F)
  } else
  {
    return(substr(haystack, hl-nl+1, hl) == needle)
  }
}



回答4:


Base now contains startsWith and endsWith. Thus the OP's question can be answered with endsWith:

> string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
> endsWith(string_name, '*')
[1] FALSE FALSE FALSE  TRUE FALSE

This is much faster than substring(string_name, nchar(string_name)) == '*'.




回答5:


here is a tidyverse solution:

string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
str_sub(string_name, -1) == "*"
[1] FALSE FALSE FALSE  TRUE FALSE

It has the benefits of being much more readable and can also be changed easily if a different location needs to be checked.



来源:https://stackoverflow.com/questions/26188663/how-to-determine-if-a-string-ends-with-another-string-in-r

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!