问题
I want to filter out the rows of a table which contain '*' in the string value of the column. Checking just that column.
string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
zz <- sapply(tx$variant_full_name, function(x) {substrRight(x, -1) =="*"})
Error in FUN(c("Agno I30N", "VP2 E17Q", "VP2 I204*", "VP3 I85F", "VP1 K73R", :
could not find function "substrRight"
The 4th value of zz should be TRUE by this.
in python there is endswith function for strings [ string_s.endswith('*') ] Is there something similar to that in R ?
Also, is it problem because of '*' as a character as it means any character ? grepl also not working.
> grepl("*^",'dddd*')
[1] TRUE
> grepl("*^",'dddd')
[1] TRUE
回答1:
*
is a quantifier in regular expressions. It tells the regular expression engine to attempt to match the preceding token "zero or more times". To match a literal, you need to precede it with two backslashes or place inside of a character class [*]
. To check if the string ends with a specific pattern, use the end of string $ anchor.
> grepl('\\*$', c('aaaaa', 'bbbbb', 'ccccc', 'dddd*', 'eee*eee'))
# [1] FALSE FALSE FALSE TRUE FALSE
You can simply do this without implementing a regular expression in base R:
> x <- c('aaaaa', 'bbbbb', 'ccccc', 'dddd*', 'eee*eee')
> substr(x, nchar(x)-1+1, nchar(x)) == '*'
# [1] FALSE FALSE FALSE TRUE FALSE
回答2:
This is simple enough that you don't need regular expressions.
> string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
> substring(string_name, nchar(string_name)) == "*"
[1] FALSE FALSE FALSE TRUE FALSE
回答3:
I use something like this:
strEndsWith <- function(haystack, needle)
{
hl <- nchar(haystack)
nl <- nchar(needle)
if(nl>hl)
{
return(F)
} else
{
return(substr(haystack, hl-nl+1, hl) == needle)
}
}
回答4:
Base now contains startsWith
and endsWith
. Thus the OP's question can be answered with endsWith
:
> string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
> endsWith(string_name, '*')
[1] FALSE FALSE FALSE TRUE FALSE
This is much faster than substring(string_name, nchar(string_name)) == '*'
.
回答5:
here is a tidyverse solution:
string_name = c("aaaaa", "bbbbb", "ccccc", "dddd*", "eee*eee")
str_sub(string_name, -1) == "*"
[1] FALSE FALSE FALSE TRUE FALSE
It has the benefits of being much more readable and can also be changed easily if a different location needs to be checked.
来源:https://stackoverflow.com/questions/26188663/how-to-determine-if-a-string-ends-with-another-string-in-r