What is the difference between chrono::month and chrono::months

问题

What is the difference between the C++20 chrono types/values month{7} and months{7}? Isn't it confusing to have two such similar names?

回答1:

Yes, it can be confusing to have both month and months when first encountering this library. However there are consistent naming conventions in this library to help reduce that confusion. And the benefit is having a clear separation of distinct semantics while retaining short intuitive names.

`months`

All "predefined" chrono::duration types are plural:

nanoseconds
microseconds
milliseconds
seconds
minutes
hours
days
weeks
months
years

So months is a chrono::duration type:

using months = duration<signed integer type of at least 20 bits,
                         ratio_divide<years::period, ratio<12>>>;

And it is exactly ¹/₁₂ of years.

static_assert(12*months{1} == years{1});

You can print it out like this:

cout << months{7} << '\n';

And the output is:

7[2629746]s

This reads as 7 units of 2,629,746s. It turns out that 2,629,746 seconds is the average length of the month in the civil calendar. Stated differently:

static_assert(months{1} == 2'629'746s);

(the exact number is not particularly important except for winning bar bets)

`month`

month (singular) on the other hand is not a chrono::duration. It is a calendrical specifier for a month of the year in the civil calendar. Or:

static_assert(month{7} == July);

This can be used to form a date like this:

auto independence_day = month{7}/4d/2020y;

The algebra of month and months reflect these different semantics. For example "July + July" is nonsensical, and thus a compile-time error:

auto x = month{7} + month{7};
         ~~~~~~~~ ^ ~~~~~~~~
error: invalid operands to binary expression ('std::chrono::month' and 'std::chrono::month')

But this makes perfect sense:

auto constexpr x = month{7} + months{7};
static_assert(x == February);

And this:

auto constexpr x = months{7} + months{7};
static_assert(x == months{14});

And yet:

auto b = February == months{14};
         ~~~~~~~~ ^  ~~~~~~~~~~
error: invalid operands to binary expression ('const std::chrono::month' and 'std::chrono::months')

I.e. month and months are not only not-equal, they are not even comparable. They are apples and oranges, if you're into fruit analogies. ;-)

There is a similar relationship between day and days. And between year and years.

If it is plural, it is a chrono::duration.

And only <chrono> has the type safety to help you ensure that these two semantically distinct and yet similar concepts do not get confused with one another in your code.

来源：https://stackoverflow.com/questions/62249520/what-is-the-difference-between-chronomonth-and-chronomonths

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