问题
In my navigation file , when I want to toggle drawer , get the following error :
TypeError: navigation.openDrawer is not a function.(In 'navigation.openDrawer()', 'navigation.openDrawer' is undefined)
This is my drawer:
const DrawerNavigator = () => {
return (
<Drawer.Navigator
initialRouteName="MYSHIFT"
>
<Drawer.Screen name="MYSHIFT" component={TopTabNavigator} />
</Drawer.Navigator>
)
}
And this is my container navigation :
const CareworkerNavigation = () => {
return (
<NavigationContainer>
<Stack.Navigator>
<Stack.Screen
name="Login"
component={LoginScreen}
options={{ headerShown: false }} />
<Stack.Screen
name="Main"
options={({ navigation }) => {
return {
headerLeft: () => <Button title="LEFT BUTTON" onPress={() => {
navigation.toggleDrawer(); // <--- this line throws an error
}} />
}
}}
component={DrawerNavigator} />
</Stack.Navigator>
</NavigationContainer>
)
}
export default CareworkerNavigation
Why I can not use navigation.toggleDrawer() in navigation options? Is is possible to remove this problem ?
回答1:
If you check the React Navigation docs, "You will need to make the drawer navigator the parent of any navigator where the drawer should be rendered on top of its UI."
React Navigation docs reference
To answer your question : Yes , it is possible.
And here you have a working example:
import React from 'react'
import { Button, View } from 'react-native'
import { NavigationContainer } from '@react-navigation/native'
import { createDrawerNavigator } from '@react-navigation/drawer'
import { createStackNavigator } from '@react-navigation/stack'
const Feed = () => <View />
const Notifications = () => <View />
const Profile = () => <View />
const FeedStack = createStackNavigator()
const Home = ({ navigation }) => (
<FeedStack.Navigator>
<FeedStack.Screen
name="Feed"
component={Feed}
options={props => {
const { toggleDrawer } = props.navigation // <-- drawer's navigation (not from stack)
return {
headerLeft: () => <Button title="LEFT BUTTON" onPress={toggleDrawer} />
}
}}
/>
</FeedStack.Navigator>
)
const Drawer = createDrawerNavigator()
export default props => {
return (
<NavigationContainer>
<Drawer.Navigator initialRouteName="Feed">
<Drawer.Screen
name="Feed"
component={Home}
options={{ drawerLabel: 'Home' }}
/>
<Drawer.Screen
name="Notifications"
component={Notifications}
options={{ drawerLabel: 'Updates' }}
/>
<Drawer.Screen
name="Profile"
component={Profile}
options={{ drawerLabel: 'Profile' }}
/>
</Drawer.Navigator>
</NavigationContainer>
)
}
回答2:
While constructing navigation
at options
, you refer to the navigation
of the stack, what cant perform draw actions, try to construct it on header itself
<Stack.Screen
name="Main"
options={() => {
return {
headerLeft: (navigation) => <Button title="LEFT BUTTON" onPress={() => {
navigation.toggleDrawer(); // <--- this line throws an error
}} />
}
}}
component={DrawerNavigator} />
https://github.com/react-navigation/react-navigation/issues/55
来源:https://stackoverflow.com/questions/61340284/is-is-possible-to-use-navigation-toggledrawer-in-navigation-options