问题
I have a simple MutationObserver
setup as a test. The HTML has a span
whose text content gets updated once per second (and a div
for messages):
<span class="tester"></span>
<div id="msg"></div>
The MutationObserver is set to watch .tester
and writes text to the #msg
div
when it observes a change. Meanwhile, a setInterval()
runs once/second to change the text in .tester
:
var target = document.querySelector('.tester');
var observer = new MutationObserver(function(mutations) {
mutations.forEach(function(mutation) {
console.log(mutation.type);
$('#msg').append(mutation.type+"<br/>")
setTimeout(function() { $('#msg').text(''); }, 500);
});
});
var config = { attributes: true, childList: true, characterData: true };
observer.observe(target, config);
setInterval(function() {
$('#msg').text('');
$('.tester').text("update: "+Math.random())
}, 1000);
I would expect this code to print once per second that the characterData has changed. According to Mozilla's docs for MutationObserver, it says about characterData: "Set to true if mutations to target's data are to be observed." Instead, I see no characterData mutations but do see two childList mutations every second.
Why am I not seeing any characterData mutations, and why am I seeing two childList mutations?
Here's a working example with CodePen.
回答1:
The reason is as Jeremy Banks said: When you use jQuery's text()
, it removes all the text nodes and then adds in new ones. That's not a change to character data, it's a change to the childList
: Removing the node that's there and replacing it with a new one.
To see a change to character data, you have to modify the existing text node's nodeValue
, and observe subtree
modifications:
var target = document.querySelector('.tester');
var observer = new MutationObserver(function(mutations) {
mutations.forEach(function(mutation) {
console.log(mutation.type);
$('#msg').append(mutation.type+"<br/>")
setTimeout(function() { $('#msg').text(''); }, 500);
});
});
var config = {
attributes: true,
childList: true,
characterData: true,
subtree: true // <=== Change, added subtree
};
observer.observe(target, config);
var timer = setInterval(function() {
$('#msg').text('');
// Change --VVVVV modifying the existing child node
$('.tester')[0].firstChild.nodeValue = "updated" + Math.random();
}, 1000);
// Stop after 10 seconds
setTimeout(function() {
clearInterval(timer);
}, 10000);
<span class="tester">x</span><!-- Change, added a starting child node -->
<div id="msg"></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
Re your question about why there are two childList
mutations, yes I think you're right: They're removing the child, then adding a new one. If we use the replaceChild method, we see only a single mutation:
var target = document.querySelector('.tester');
var observer = new MutationObserver(function(mutations) {
mutations.forEach(function(mutation) {
console.log(mutation.type);
$('#msg').append(mutation.type+"<br/>")
setTimeout(function() { $('#msg').text(''); }, 500);
});
});
var config = {
attributes: true,
childList: true,
characterData: true,
subtree: true // <=== Change, added subtree
};
observer.observe(target, config);
var timer = setInterval(function() {
$('#msg').text('');
// Change --VVVVV modifying the existing child node
var text = document.createTextNode("updated" + Math.random());
var parent = $('.tester')[0];
parent.replaceChild(text, parent.firstChild);
}, 1000);
// Stop after 10 seconds
setTimeout(function() {
clearInterval(timer);
}, 10000);
<span class="tester">x</span><!-- Change, added a starting child node -->
<div id="msg"></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
来源:https://stackoverflow.com/questions/35640501/why-does-mutationobserver-fire-twice-for-childlist-but-never-for-characterdata