问题
So, in Haskell, it's really easy to do this:
data Foo = Bar | Baz
deriving (Read, Show)
This is great, but I'd like to be able to pass some data as a string from Haskell to the Elm language. The languages are similar enough that, if I had a Haskell implementation of Read, I could easily convert it to Elm by hand.
The problem is, when I use deriving, the function is automatically generated, but I can't actually see what it does.
I'm wondering, is there a way to automatically generate the code for parsing and showing using Read and Show, so that I could actually see the code itself?
回答1:
You can use the the -ddump-deriv
GHC option to see the code for derived instances:
ghc -ddump-deriv test.hs
[1 of 1] Compiling Test ( test.hs, test.o )
==================== Derived instances ====================
Derived instances:
instance GHC.Show.Show Test.FooBar where
GHC.Show.showsPrec _ Test.Foo = GHC.Show.showString "Foo"
GHC.Show.showsPrec _ Test.Bar = GHC.Show.showString "Bar"
GHC.Show.showList = GHC.Show.showList__ (GHC.Show.showsPrec 0)
Generic representation:
Generated datatypes for meta-information:
Representation types:
回答2:
For stack:
stack build --ghc-options="-ddump-deriv"
Output in my specific case is: .stack-work/dist/x86_64-linux-nix/Cabal-2.4.0.1/build/app/app-tmp/src/
来源:https://stackoverflow.com/questions/18538055/how-to-view-the-generated-code-for-derived-instances-deriving-in-haskell