问题
I have this code which generates random number from an array, at a particular condition (when x and y both are equal to zero). I want the control to jump to the label. But the control never jumps to the label in any condition. I wanted to know that whether I am doing it right or not?
int[] arr = {0, 1, 2};
Random rn = new Random();
label: {
//some code
if (x != 0 && y !=0) {
//some code
} else {
break label;
}
}
回答1:
Try to Avoid using labels. What you could do there, is:
while(true) {
if(x == 0 && y == 0) {
break;
}
// some stuff with x and y
}
回答2:
Without examining whether you should, yes, you can use labeled statements with if
in Java. According to the 1.7 specification
The Identifier is declared to be the label of the immediately contained Statement. [...] identifier statement labels are used with break (§14.15) or continue (§14.16) statements appearing anywhere within the labeled statement.
It goes on (emphasis added)
If the statement is labeled by an Identifier and the contained Statement completes abruptly because of a break with the same Identifier, then the labeled statement completes normally. In all other cases of abrupt completion of the Statement, the labeled statement completes abruptly for the same reason.
So if you break
an if
block (remember a block is a statement), you can exit the if
body. Let's test it:
public static void main(String[] args) {
if (true) label: {
if (args != null)
break label;
System.out.println("doesn't get here");
}
System.out.println("Outside of labeled block");
}
Output:
Outside of labeled block
回答3:
The break
statement breaks loops and does not transfer control to the label.
Using a label with break
is for when you have inner and outer loops. An unlabeled break
breaks the inner most loop (the one you are in) whereas a labeled break
allows you to specify an outer loop.
See: http://docs.oracle.com/javase/tutorial/java/nutsandbolts/branch.html
Specifically the BreakWithLabelDemo
回答4:
I suggest that you use a recursive function.
public void work(){
// some code
if (x != 0 && y != 0) {
//some code
} else {
work();
}
}
You cannot use break
without loops
回答5:
As far as I know, labels cannot be used arbitrarily around {}
, you need to do them to mark a for, while or do-while loop
来源:https://stackoverflow.com/questions/14835815/using-label-and-break-in-if-else-statement