问题
Using numpy.interp
I am able to compute the one-dimensional piecewise linear interpolant to a function with given values at discrete data-points.
Is it a similar function to return me the logarithmic interpolation?
回答1:
In the past, I've just wrapped the normal interpolation to do it in log-space, i.e.
def log_interp(zz, xx, yy):
logz = np.log10(zz)
logx = np.log10(xx)
logy = np.log10(yy)
return np.power(10.0, np.interp(logz, logx, logy))
Personally, I much prefer the scipy interpolation functions (as @mylesgallagher mentions), for example:
import scipy as sp
import scipy.interpolate
def log_interp1d(xx, yy, kind='linear'):
logx = np.log10(xx)
logy = np.log10(yy)
lin_interp = sp.interpolate.interp1d(logx, logy, kind=kind)
log_interp = lambda zz: np.power(10.0, lin_interp(np.log10(zz)))
return log_interp
Then you can just call this as a function on an arbitrary value.
回答2:
If I am understanding you correctly, you have some discrete data that you want to get a smooth set of values that would arise in between the values you have. I am assuming you don't want an equation of a log function that approximates the data.
Unfortunately numpy does not have anything outside of the linear piecewise interpolation, however if you look into using SciPy it does have a more powerful interpolation function. See SciPy's interpolate documentation for more detail.
It includes more complex interpolations like 'cubic' interpolations which will give you very smooth approximations, but it won't be a logarithm and it won't give you an equation.
If you want an equation what you are looking for is a regression technique not interpolation, but I don't think you are.
来源:https://stackoverflow.com/questions/29346292/logarithmic-interpolation-in-python