问题
Maybe I'm just missing something in the docs, but it seem it's not possible with GLM to take the transpose of a vector. I also see no mat3x1 or mat1x3 types. Also glm::transpose doesn't work for vectors. Am I missing something or is this just a feature lacking in GLM?
回答1:
GLM is based on GLSL, where there's simply no need to transpose a vector. If you do vector/matrix multiplication, it will multiply the vector in the way that works for the size of the matrix (unless it would have to change the order of the multiplication). So if you have a mat4
and do mat4*vec4
, your vec4
is considered a column vector. If you do vec4*mat4
, it is considered a row vector. If you do mat2x4*vec4
, you get an error, while vec4*mat2x4
works (as a row vector).
So in general, there's no reason to need to "transpose" a vector. The system simply does whatever works.
回答2:
As a reference for people looking for how to transpose a vector (primarily for calculating outer products - u vT) in GLSL/GLM; its:
glm::core::function::matrix::outerProduct(u, v)
Nicol's GLM link now 404s as their API links have changed format from:
OLD Link: http://glm.g-truc.net/api-0.9.4/a00133.html#ga5d896e8651512fc098a677dbe403eeac
New Link: http://glm.g-truc.net/0.9.4/api/a00133.html#ga5d896e8651512fc098a677dbe403eeac
来源:https://stackoverflow.com/questions/9863875/glm-how-to-transpose-a-vector