Python Docx - how to number headings?

问题

There is a good example for Python Docx.

I have used multiple document.add_heading('xxx', level=Y) and can see when I open the generated document in MS Word that the levels are correct.

What I don't see is numbering, such a 1, 1.1, 1.1.1, etc I just see the heading text.

How can I display heading numbers, using Docx ?

回答1:

Alphanumeric heading prefixes are automatically created based on the outline style and level of the heading. Set the outline style and insert the correct level and you will get the numbering.

Numbering style has not yet been implemented. From documentation: _NumberingStyle objects class docx.styles.style._NumberingStyle[source] A numbering style. Not yet implemented.

However, if set headings (e.g., paragraph.style = document.styles['Heading 1']), then it should default to the latent numbering style of that heading.

回答2:

this answer will realy help you

first you need to new a without number header like this

paragraph = document.add_paragraph()
paragraph.style = document.styles['Heading 4']

then you will have xml word like this

<w:pPr>
<w:pStyle w:val="4"/>
</w:pPr>

then you can access xml word "pStyle" property and change it using under code

header._p.pPr.pStyle.set(qn('w:val'), u'4FDD')

final, open word file you will get what you want !!!

回答3:

def __str__(self):
    if self.nivel == 1: 
        return str(Level.count_1)+'.- '+self.titulo
    elif self.nivel==2: #Imprime si es del nivel 2
        return str(Level.count_1)+'.'+str(Level.count_2)+'.- '+self.titulo
    elif self.nivel==3: #Imprime si es del nivel 3
        return str(Level.count_1)+'.'+str(Level.count_2)+'.'+str(Level.count_3)+'.- '+self.titulo

来源：https://stackoverflow.com/questions/53870457/python-docx-how-to-number-headings

标签

python

python-docx