Problem with convert jsonObject to string jsonarray and show in dialog

浪子不回头ぞ 提交于 2020-06-17 08:04:47

问题


i need help for show array 3 items in dialog

items in array : InvernaderoId, Name and Invernarder

I have a problem with convert jsonobject to jsonarray

JsonObject:

{"data":[{"invernaderoId":"1","name":"inver B","Invernarder":"inv1"},{"invernaderoId":"2","name":"inver C","Invernarder":"inv2"},{"invernaderoId":"3","name":"inv13","Invernarder":"inv3"},{"invernaderoId":"4","name":"inv14 A","Invernarder":"HTFRA14A"}]}

Convert to JsonArray with JSONArray arr = js.getJSONArray("data");

Result example:

[{"invernaderoId":"1","name":"inver B","Invernarder":"inv1"},{"invernaderoId":"2","name":"sd 12 C","Invernarder":"HTESP12C"},{"invernaderoId":"3","name":"s13","Invernarder":"sd"},{"invernaderoId":"4","name":"ds 14 A","Invernarder":"ds"}]

Code the replace array string:

  String[] arr2 = arr.toString().replace("},{", " ,").split(" ");

and

final String[] employes= arr2;

Code dialog:

 new AlertDialog.Builder(getContext())
                            .setTitle("Selected one")
                            .setSingleChoiceItems(employes, itemSelected, new DialogInterface.OnClickListener() {
                                @Override
                                public void onClick(DialogInterface dialogInterface, int selectedIndex) {
                                    String nombreselect = employes[selectedIndex];
                                    employes.setText(nombreselect);
                                }
                            })
                            .setPositiveButton("Ok", null)
                            .setNegativeButton("Cancel", null)
                            .show();
                }
            });

Viewer in Dialog select:


回答1:


you can iterate through the JSONArray elements and add them into a String array, then feed your AlertDialg with this String array

final String jsonResponse = "{   \"data\":[      {\n" +
        "         \"invernaderoId\":\"1\",\n" +
        "         \"name\":\"inver B\",\n" +
        "         \"Invernarder\":\"inv1\"\n" +
        "      \n" +
        "},\n" +
        "      {\n" +
        "         \"invernaderoId\":\"2\",\n" +
        "         \"name\":\"inver C\",\n" +
        "         \"Invernarder\":\"inv2\"\n" +
        "      \n" +
        "},\n" +
        "      {\n" +
        "         \"invernaderoId\":\"3\",\n" +
        "         \"name\":\"inv13\",\n" +
        "         \"Invernarder\":\"inv3\"\n" +
        "      \n" +
        "},\n" +
        "      {\n" +
        "         \"invernaderoId\":\"4\",\n" +
        "         \"name\":\"inv14 A\",\n" +
        "         \"Invernarder\":\"HTFRA14A\"\n" +
        "      \n" +
        "}\n" +
        "   \n" +
        "]\n" +
        "}";

try {
    JSONObject js = new JSONObject(jsonResponse);
    JSONArray arr = js.getJSONArray("data");
    String[] list = new String[arr.length()];
    for (int i = 0; i <= arr.length() - 1; i++) {
        JSONObject element = arr.getJSONObject(i);
        String InvernaderoId = "\"invernaderoId\":\"" + element.getString("invernaderoId") + "\", ";
        String Name = "\"name\":\"" + element.getString("name") + "\", ";
        String Invernarder = "\"Invernarder\":\"" + element.getString("Invernarder") + "\"";

        list[i] = InvernaderoId + Name + Invernarder;
    }

    AlertDialog.Builder builder = new AlertDialog.Builder(getContext());
    builder.setTitle("Title")
            .setSingleChoiceItems(list, -1, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int position) {

                    Toast.makeText(getContext(), "Position: " + position, Toast.LENGTH_SHORT).show();

                }
            }).setPositiveButton("Ok", null)
            .setNegativeButton("Cancel", null)
            .show();

} catch (JSONException e) {
    e.printStackTrace();
}

This is the result




回答2:


  String[] arr2 = arr.toString().replace("},{", " ,").split(" ");

since you have an array, the easiest would be to pass the json array properly, create an adapter (EG. ArrayAdapter<DataModel>) and call setAdapter on the builder. In the adapter subclass you can control how the single entry is being rendered on the dialog



来源:https://stackoverflow.com/questions/62391076/problem-with-convert-jsonobject-to-string-jsonarray-and-show-in-dialog

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!