问题
I need a regular expression for hours in PHP, I am using ereg. I need it to accept 1-23 without leading zeros.
^([1-9])|([1][0-9])|([2][0-3])$
That's what I am using but I cannot find where is the mistake.
回答1:
Alternations (|) apply to everything in the surrounding group or globally if not in a group. So in your pattern, the ^ only applies to the first pattern and the $ only applies to the last pattern. In other words, your pattern matches any string which begins with a digit from 1 to 9, contains a 1 followed by a digit from 0 to 9, or ends with a 2 followed by a digit from 0 to 3.
Try putting the different options in one group:
^([1-9]|1[0-9]|2[0-3])$
Also note, 24-hour time starts at 00:00, so your pattern should look more like this:
^(1?[0-9]|2[0-3])$
Or this, if you need the hour to be 2 digits:
^([01][0-9]|2[0-3])$
来源：https://stackoverflow.com/questions/22256002/regular-expression-syntax-for-hours