Javascript, extending ES6 class setter will inheriting getter

问题

In Javascript, with the following illustration code:

class Base {
   constructor() {  this._val = 1   }
   get val()     { return this._val }
}

class Xtnd extends Base {
   set val(v)    { this._val = v }
}

let x = new Xtnd();
x.val = 5;
console.log(x.val);  // prints 'undefined'

the instance x will not inherit get val()... from Base class. As it is, Javascript treat the absence of a getter, in the presence of the setter, as undefined.

I have a situation in which I have many classes that all have the exact same set of getters but unique setters. Currently, I simply replicate the getters in each class, but I'm refactoring and want to eliminate the redundant code.

Is there a way to tell JS to keep the getter from the base class, or does anyone have an elegant solution to this problem?

回答1:

This limitation is due to how JavaScript treats property accessors behind the scenes. In ECMAScript 5, you end up with a prototype chain that has a property descriptor for val with a get method defined by your class, and a set method that is undefined.

In your Xtnd class you have another property descriptor for val that shadows the entire property descriptor for the base class's val, containing a set method defined by the class and a get method that is undefined.

In order to forward the getter to the base class implementation, you'll need some boilerplate in each subclass unfortunately, but you won't have to replicate the implementation itself at least:

class Base {
   constructor() {  this._val = 1   }
   get val()     { return this._val }
}

class Xtnd extends Base {
   get val()     { return super.val }
   set val(v)    { this._val = v }
}

let x = new Xtnd();
x.val = 5;
console.log(x.val);  // prints '5'

来源：https://stackoverflow.com/questions/53584705/javascript-extending-es6-class-setter-will-inheriting-getter

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javascript

extend

es6-class

boilerplate