Python - take out the data inside cell of dataframe to another cells

问题

This is the data in single cell of dataframe with 14 columns. Cell is the element of column. There are 45k+ this kind of cells, to do it manually is a hell.

one cell data

I'd like to do with this cell 3 things:

1. move text part with address, state, zip - to another column;
2. delete the hooks () of cell;
3. separate for 2 columns longitude and latitude.

How it's possible to do?

回答1:

Here's a simple, working example with 2 data points:

text1 = """30881 EKLUTNA LAKE RD
CHUGIAK, AK 99567
(61.4478, -149.3136)"""

text2 = """30882 FAKE STR
CHUGIAK, AK 98817
(43.4478, -119.3136)"""

d = {'col1': [text1, text2]}

df = pd.DataFrame(data=d)

def fix(row):
  #We split the text by newline
  address, cp, latlong =  row.col1.split('\n')

  #We get the latitude and longitude by splitting by a comma
  latlong_vec = latlong[1:-1].split(',')

  #This part isn't really necessary but we create the variables for claity
  lat = float(latlong_vec[0])
  long = float(latlong_vec[1])

  return pd.Series([address + ". " + cp, lat, long])


df[['full address', 'lat', 'long']] = df.apply(fix, axis = 1)

Output of the 3 new columns:

df['full address']
0    30881 EKLUTNA LAKE RD. CHUGIAK, AK 99567
1           30882 FAKE STR. CHUGIAK, AK 98817

df['lat']

0    61.4478
1    43.4478
Name: lat, dtype: float64

df['long']

0   -149.3136
1   -119.3136
Name: long, dtype: float64

Name: full address, dtype: object

来源：https://stackoverflow.com/questions/61746266/python-take-out-the-data-inside-cell-of-dataframe-to-another-cells