问题
I want to write a single function, that accepts a &str
, a String
and a borrowed &String
. I've written the following 2 functions:
fn accept_str_and_ref_string(value: &str) {
println!("value: {}", value);
}
fn accept_str_and_string<S: Into<String>>(value: S) {
let string_value: String = value.into();
println!("string_value: {}", string_value);
}
fn main() {
let str_foo = "foo";
let string_foo = String::from("foo");
accept_str_and_ref_string(str_foo);
accept_str_and_ref_string(&string_foo);
accept_str_and_string(str_foo);
accept_str_and_string(string_foo);
}
Is it possible to implement one function so that I can do this:
accept_all_strings(str_foo);
accept_all_strings(&string_foo);
accept_all_strings(string_foo);
回答1:
You can use the AsRef<str> trait:
// will accept any object that implements AsRef<str>
fn print<S: AsRef<str>>(stringlike: S) {
// call as_ref() to get a &str
let str_ref = stringlike.as_ref();
println!("got: {:?}", str_ref)
}
fn main() {
let a: &str = "str";
let b: String = String::from("String");
let c: &String = &b;
print(a);
print(c);
print(b);
}
The print
function will support any type that implements AsRef<str>
, which includes &str
, String
and &String
.
来源:https://stackoverflow.com/questions/55079070/how-to-accept-str-string-and-string-in-a-single-function