String as a Model

南楼画角 提交于 2020-05-25 03:38:12

问题


I thought this should have been an easier task :

Edit:

It seems till this day Asp.Net MVC couldn't provide a neat solution on this case:

If you want to pass a simple string as a model and you don't have to define more classes and stuff to do so... Any ideas ??

Pass simple string as a model


here I'm trying to have a simple string model.

I'm getting this error :

"Value cannot be null or empty" / "Parameter name: name" 

The View :

@model string
@using (Html.BeginForm())
{ 
        <span>Please Enter the code</span> 
        @Html.TextBoxFor(m => m) // Error Happens here
        <button id="btnSubmit" title="Submit"></button>
}

The Controller :

public string CodeText { get; set; }

public HomeController()
{
    CodeText = "Please Enter MHM";
}

[HttpGet]
public ActionResult Index()
{
    return View("Index", null, CodeText);
}

[HttpPost]
public ActionResult Index(string code)
{
    bool result = false;
    if (code == "MHM")
        result = true;

    return View();
}

回答1:


Either wrap the string in a view model object:

Model:

public class HomeViewModel
{
    public string CodeText { get; set; }
}

Controller:

private HomeViewModel _model;

public HomeController()
{
    _model = new HomeViewModel { CodeText = "My Text" };
}

[HttpGet]
public ActionResult Index()
{
    return View("Index", _model);
}

View:

@Html.TextBoxFor(m => m.CodeText);    

Or use EditorForModel:

@Html.EditorForModel()



回答2:


There's a much cleaner way of passing a string as a model into your view. You just need to use named parameters when returning your view:

[HttpGet]
public ActionResult Index()
{
    string myStringModel = "I am passing this string as a model in the view";
    return View(model:myStringModel);
}



回答3:


I know you've already accepted an answer here - I'm adding this because there's a general gotcha associated with using a string model.

String as a model type in MVC is a nightmare, because if you do this in a controller:

string myStringModel = "Hello world";
return View("action", myStringModel);

It ends up choosing the wrong overload, and passing the myStringModel as a master name to the view engine.

In general it is easier simply to wrap it in a proper model type, as the accepted answer describes, but you can also simply force the compiler to choose the correct overload of View() by casting the string to object:

return View("action", (object)myStringModel);

The other issue you're having here of using TextBoxFor having issues with an 'unnamed' model - well you shouldn't be surprised by that... The only reason to use TextBoxFor is to ensure the fields are named correctly for binding when the underlying value is a property on a model type. In this case there is no name, because you're passing it as a top-level model type for a view - so you it could be argued that you shouldn't be using TextBoxFor() in the first place.



来源:https://stackoverflow.com/questions/16852537/string-as-a-model

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!