Pastebin API Paste Data

问题

I've been trying to get the pastebin API to instead of telling me the pastebin link , just output the raw data. The PHP code is this :

<?php

$api_dev_key        = 'Stackoverflow(fake key)';    
$api_paste_code         = 'API.'; // your paste text
$api_paste_private      = '1'; // 0=public 1=unlisted 2=private
$api_paste_expire_date  = 'N';
$api_paste_format       = 'php';
$api_paste_code     = urlencode($api_paste_code);

$url            = 'http://pastebin.com/api/api_post.php';
$ch             = curl_init($url);

?>

Normally this would upload the $api_paste_code into pastebin , showing up like pastebin.com/St4ck0v3RFL0W , but instead I want it to generate the raw data.

The raw data link is http://pastebin.com/raw.php?i= , can anyone help?

Reference : http://pastebin.com/api

回答1:

First off, please note that you must send a POST request to the pastebin.com API, not GET. So don't use urlencode() on your input data!

To get the raw paste url from the page url, you have several options. But the easiest is probably:

$apiResonse = 'http://pastebin.com/ABC123';
$raw        = str_replace('m/', 'm/raw.php?i=', $apiResponse);

Finally, here is a complete example:

<?php
$data = 'Hello World!';

$apiKey  = 'xxxxxxx';                         // get it from pastebin.com
$apiHost = 'http://pastebin.com/';

$postData = array(
    'api_dev_key'    => $apiKey,             // your dev key
    'api_option'     => 'paste',             // action to perform
    'api_paste_code' => utf8_decode($data),  // the paste text
);

$ch = curl_init();
curl_setopt_array($ch, array(
    CURLOPT_URL             => "{$apiHost}api/api_post.php",
    CURLOPT_RETURNTRANSFER  => 1,
    CURLOPT_POST            => 1,
    CURLOPT_POSTFIELDS      => http_build_query($postData),
));

$result = curl_exec($ch); // on success, some string like 'http://pastebin.com/ABC123'
curl_close($ch);

if ($result) {
    $pasteId = str_replace($apiHost, '', $result);
    $rawLink = "{$apiHost}raw.php?i={$pasteId}";

    echo "Created new paste.\r\n Paste ID:\t{$pasteId}\r\n Page Link:\t{$result}\r\n Raw Link:\t{$rawLink}\r\n";
}

Running the above code, outputs:

c:\xampp\htdocs>php pastebin.php
Created new paste.
 Paste ID:      Bb8Ehaa7
 Page Link:     http://pastebin.com/Bb8Ehaa7
 Raw Link:      http://pastebin.com/raw.php?i=Bb8Ehaa7

回答2:

As far as I see, the response contains the Pastebin URL generated when the content is created. An Url like this:

http://pastebin.com/UIFdu235s

So what you only need is to get rid of "http://pastebin.com/" doing:

$id = str_replace("http://pastebin.com/", "", $url_received_on_last_step);

And then, append it to the raw url you provided:

$url_raw = "http://pastebin.com/raw.php?i=".$id;

And you'll get the raw data.

来源：https://stackoverflow.com/questions/13041282/pastebin-api-paste-data

标签

php

pastebin