问题
In the below code, an error is thrown when employee_code_list is longer than 2000 items as mentioned below. However, it works perfectly when the list is under 2000 items.
query = session.query(TblUserEmployee, TblUser).filter(
and_(
(TblUser.UserId == TblUserEmployee.EmployeeId),
(func.lower(TblUserEmployee.EmployeeCode).in_(employee_code_list)),
(TblUser.OrgnId == MIG_CONSTANTS.context.organizationid),
(TblUser.UserTypeId == user_type)
))
results = query.all()
This is the relevant part of the error that is thrown:
File ""site-packages\sqlalchemy\util\compat.py"", line 203, in raise_from_cause
File ""site-packages\sqlalchemy\engine\base.py"", line 1193, in _execute_context
File ""site-packages\sqlalchemy\engine\default.py"", line 507, in do_execute
DBAPIError: (pyodbc.Error) ('07002', u'[07002] [Microsoft][ODBC Driver 17 for SQL Server]COUNT field incorrect or syntax error (0) (SQLExecDirectW)') [SQL: u'SELECT [tblTaxGroup].[TaxGroupId] AS [tblTaxGroup_TaxGroupId], [tblTaxGroup].[Code] AS [tblTaxGroup_Code], [tblTaxGroupCenter].[CenterId] AS [tblTaxGroupCenter_CenterId] \nFROM [tblTaxGroup], [tblTaxGroupCenter], [tblCenterTax] \nWHERE [tblTaxGroup].[OrganizationId] = ? AND [tblTaxGroup].[Void] = 0 AND [tblTaxGroup].[TaxGroupId] = [tblTaxGroupCenter].[TaxGroupId] AND [tblTaxGroup].[Code] IN (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, 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?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) AND [tblCenterTax].[CenterId] = [tblTaxGroupCenter].[CenterId] AND [tblCenterTax].[TaxGroupId] = [tblTaxGroupCenter].[TaxGroupId] AND [tblCenterTax].[ApplyToVendors] = 1 AND [tblTaxGroupCenter].[Void] = 0'] [parameters: (u'A8D7DD91-152D-4042-8205-8EEB1DB2A283', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', u'SGST18', .......u'SGST18')] (Background on this error at: http://sqlalche.me/e/dbapi)
This is the connector that I am using:
engine_meta = create_engine(
'mssql+pyodbc://' +
global_json["target_database_username"] + ':' +
global_json["target_database_password"] + '@' +
global_json["target_database_server_ip"] + "/" +
global_json["target_database_name"],
implicit_returning=False)
We have recently changed our connector from pymssql to pyodbc for some other reasons. This problem was not present when we were using pymssql
Edit: Copied a little more of the error message. Had cropped it as it was showing details of my organization db. And since the same query works for lesser number of items, I am sure it is not a syntax error. Note: The error is not due to same values being substituted, have tried it for a case with all unique values too, still has the same error.
回答1:
Your query is basically forcing SQLAlchemy to emit a query with 2000+ parameters (SELECT * WHERE Y IN (list of 2000+ values)
). Different RDBMS's (and different drivers) have limits on the number of parameters you may have.
Although your stack trace doesn't cover the exact error, I notice that you're using SQL Server and the numbers you're talking about are suspiciously close to a 2100 parameter limit SQL Server imposes under certain circumstances (see Parameters per user-defiend function on this Microsoft knowledge article). I would be willing to bet that this is what you're running into.
The easiest approach you can take is to simply run your query in batches for each, say, 1000 items in employee_code_list
:
results = []
batch_size = 1000
batch_start = 0
while batch_start < len(employee_code_list):
batch_end = batch_start + batch_size
employee_code_batch = employee_code_list[batch_start:batch_end]
query = session.query(TblUserEmployee, TblUser).filter(
and_(
(TblUser.UserId == TblUserEmployee.EmployeeId),
(func.lower(TblUserEmployee.EmployeeCode).in_(employee_code_batch)),
(TblUser.OrgnId == MIG_CONSTANTS.context.organizationid),
(TblUser.UserTypeId == user_type)
))
results.append(query.all())
batch_start += batch_size
In this example we're creating an empty results list that we will append each batch of results to. We're setting a batch size of 1000 and a start position of 0 (the first item in employee_code_list
). We're then running your query for each batch of 1000, and appending the results to results
, until there are no records left to query in employee_code_list
.
There are other approaches of course, but this is one that won't require you to use a different RDBMS, and might be easiest to work into your code.
来源:https://stackoverflow.com/questions/50212104/pyodbc-sqlalchemy-fails-for-more-than-2100-items