How to filter a html table using simple javascript?

你说的曾经没有我的故事 提交于 2020-04-27 18:29:35

问题


I have a code to filter a table. It will filter only based on first column. How to make it filter second column alone. Also how to filter complete table?

I am not able to figure out the method to do it. I trying to get help to do it without any other external libraries.

<input type="text" id="myInput" onkeyup="myFunction()" placeholder="Search for names.." title="Type in a name">

<table id="myTable">
  <tr class="header">
    <th style="width:60%;">Name</th>
    <th style="width:40%;">Country</th>
  </tr>
  <tr>
    <td>Alfreds Futterkiste</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Berglunds snabbkop</td>
    <td>Sweden</td>
  </tr>
  <tr>
    <td>Island Trading</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Koniglich Essen</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Laughing Bacchus Winecellars</td>
    <td>Canada</td>
  </tr>
  <tr>
    <td>Magazzini Alimentari Riuniti</td>
    <td>Italy</td>
  </tr>
  <tr>
    <td>North/South</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Paris specialites</td>
    <td>France</td>
  </tr>
</table>

<script>
function myFunction() {
  var input, filter, table, tr, td, i;
  input = document.getElementById("myInput");
  filter = input.value.toUpperCase();
  table = document.getElementById("myTable");
  tr = table.getElementsByTagName("tr");
  for (i = 0; i < tr.length; i++) {
    td = tr[i].getElementsByTagName("td")[0];
    if (td) {
      if (td.innerHTML.toUpperCase().indexOf(filter) > -1) {
        tr[i].style.display = "";
      } else {
        tr[i].style.display = "none";
      }
    }       
  }
}
</script>

JS Fiddle


回答1:


You are almost there. All you needed to do was to create another for loop and iterate over all td elements in the row, and filter using them. By doing so, if you add any columns in future, the filter will continue to work.

In the snippet below, I have done that, and slightly modified the hiding logic. I am hiding all the rows to begin with, and if a match is found, I unhide it.

for (i = 1; i < tr.length; i++) {
    // Hide the row initially.
    tr[i].style.display = "none";

    td = tr[i].getElementsByTagName("td");
    for (var j = 0; j < td.length; j++) {
      cell = tr[i].getElementsByTagName("td")[j];
      if (cell) {
        if (cell.innerHTML.toUpperCase().indexOf(filter) > -1) {
          tr[i].style.display = "";
          break;
        } 
      }
    }
}

function myFunction() {
  var input, filter, table, tr, td, cell, i, j;
  input = document.getElementById("myInput");
  filter = input.value.toUpperCase();
  table = document.getElementById("myTable");
  tr = table.getElementsByTagName("tr");
  for (i = 1; i < tr.length; i++) {
    // Hide the row initially.
    tr[i].style.display = "none";
  
    td = tr[i].getElementsByTagName("td");
    for (var j = 0; j < td.length; j++) {
      cell = tr[i].getElementsByTagName("td")[j];
      if (cell) {
        if (cell.innerHTML.toUpperCase().indexOf(filter) > -1) {
          tr[i].style.display = "";
          break;
        } 
      }
    }
  }
}
<input type="text" id="myInput" onkeyup="myFunction()" placeholder="Search for names.." title="Type in a name">

<table id="myTable">
  <tr class="header">
    <th style="width:60%;">Name</th>
    <th style="width:40%;">Country</th>
  </tr>
  <tr>
    <td>Alfreds Futterkiste</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Berglunds snabbkop</td>
    <td>Sweden</td>
  </tr>
  <tr>
    <td>Island Trading</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Koniglich Essen</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Laughing Bacchus Winecellars</td>
    <td>Canada</td>
  </tr>
  <tr>
    <td>Magazzini Alimentari Riuniti</td>
    <td>Italy</td>
  </tr>
  <tr>
    <td>North/South</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Paris specialites</td>
    <td>France</td>
  </tr>
</table>

Note: I would suggest using innerText instead of innerHTML for filtering. If you have HTML content in the cells, innerHTML might interfere with the filtering.




回答2:


You can do:

function myFunction() {
  const filter = document.querySelector('#myInput').value.toUpperCase();
  const trs = document.querySelectorAll('#myTable tr:not(.header)');
  trs.forEach(tr => tr.style.display = [...tr.children].find(td => td.innerHTML.toUpperCase().includes(filter)) ? '' : 'none');
}
<input type="text" id="myInput" onkeyup="myFunction()" placeholder="Search for names.." title="Type in a name">

<table id="myTable">
  <tr class="header">
    <th style="width:60%;">Name</th>
    <th style="width:40%;">Country</th>
  </tr>
  <tr>
    <td>Alfreds Futterkiste</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Berglunds snabbkop</td>
    <td>Sweden</td>
  </tr>
  <tr>
    <td>Island Trading</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Koniglich Essen</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Laughing Bacchus Winecellars</td>
    <td>Canada</td>
  </tr>
  <tr>
    <td>Magazzini Alimentari Riuniti</td>
    <td>Italy</td>
  </tr>
  <tr>
    <td>North/South</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Paris specialites</td>
    <td>France</td>
  </tr>
</table>



回答3:


With

td = tr[i].getElementsByTagName("td")[0];

you're only selecting the first td. Instead, check for if some of the tds have the string in question:

function myFunction() {
  const input = document.getElementById("myInput");
  const inputStr = input.value.toUpperCase();
  document.querySelectorAll('#myTable tr:not(.header)').forEach((tr) => {
    const anyMatch = [...tr.children]
      .some(td => td.textContent.toUpperCase().includes(inputStr));
    if (anyMatch) tr.style.removeProperty('display');
    else tr.style.display = 'none';
  });
}
<input type="text" id="myInput" onkeyup="myFunction()" placeholder="Search for names.." title="Type in a name">

<table id="myTable">
  <tr class="header">
    <th style="width:60%;">Name</th>
    <th style="width:40%;">Country</th>
  </tr>
  <tr>
    <td>Alfreds Futterkiste</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Berglunds snabbkop</td>
    <td>Sweden</td>
  </tr>
  <tr>
    <td>Island Trading</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Koniglich Essen</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Laughing Bacchus Winecellars</td>
    <td>Canada</td>
  </tr>
  <tr>
    <td>Magazzini Alimentari Riuniti</td>
    <td>Italy</td>
  </tr>
  <tr>
    <td>North/South</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Paris specialites</td>
    <td>France</td>
  </tr>
</table>



回答4:


Only change

td = tr[i].getElementsByTagName("td")[0];

to

td = tr[i].getElementsByTagName("td")[1];

should work fine.

Update

Add all columns search.

function myFunction() {
  var input, filter, table, tr, td, i;
  input = document.getElementById("myInput");
  filter = input.value.toUpperCase();
  table = document.getElementById("myTable");
  tr = table.getElementsByTagName("tr");
  for (var i = 0; i < tr.length; i++) {
    var tds = tr[i].getElementsByTagName("td");
    var flag = false;
    for(var j = 0; j < tds.length; j++){
      var td = tds[j];
      if (td.innerHTML.toUpperCase().indexOf(filter) > -1) {
        flag = true;
      } 
    }
    if(flag){
        tr[i].style.display = "";
    }
    else {
        tr[i].style.display = "none";
    }
  }
}
<input type="text" id="myInput" onkeyup="myFunction()" placeholder="Search for names.." title="Type in a name">

<table id="myTable">
  <tr class="header">
    <th style="width:60%;">Name</th>
    <th style="width:40%;">Country</th>
  </tr>
  <tr>
    <td>Alfreds Futterkiste</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Berglunds snabbkop</td>
    <td>Sweden</td>
  </tr>
  <tr>
    <td>Island Trading</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Koniglich Essen</td>
    <td>Germany</td>
  </tr>
  <tr>
    <td>Laughing Bacchus Winecellars</td>
    <td>Canada</td>
  </tr>
  <tr>
    <td>Magazzini Alimentari Riuniti</td>
    <td>Italy</td>
  </tr>
  <tr>
    <td>North/South</td>
    <td>UK</td>
  </tr>
  <tr>
    <td>Paris specialites</td>
    <td>France</td>
  </tr>
</table>


来源:https://stackoverflow.com/questions/51187477/how-to-filter-a-html-table-using-simple-javascript

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