问题
I am trying to pass a list to python from cpp and taking it back. Initially I tried to pass a single value and get back one value. It worked. Now I am trying to pass the complete array/list Below is my cpp code:
#include <iostream>
#include <Python.h>
#include <numpy/arrayobject.h>
#include <typeinfo>
using namespace std;
int main()
{
Py_Initialize();
PyObject *sys = PyImport_ImportModule("sys");
PyObject *path = PyObject_GetAttrString(sys, "path");
PyList_Append(path, PyString_FromString("."));
PyObject *pName, *pModule, *pDict, *pFunc, *pArgs, *pValue;
// Build the name object
pName = PyString_FromString("mytest");
// Load the module object
pModule = PyImport_Import(pName);
// pDict is a borrowed reference
pDict = PyModule_GetDict(pModule);
// pFunc is also a borrowed reference
pFunc = PyObject_GetAttrString(pModule, "stuff");
if (!PyCallable_Check(pFunc))
PyErr_Print();
PyObject *list = PyList_New (5);
Py_ssize_t size = PyList_GET_SIZE(list);
for(Py_ssize_t s = 0; s < size; s++ )
{
PyList_SetItem(list, s, Py_BuildValue("d", 2.5));
}
PyObject* result = PyObject_CallObject(pFunc, list);
if(result==NULL)
{cout << "FAILED ..!!" << endl;}
cout << result << endl;;
return 0;
}
I am always getting "FAILED..!!".
Here is my mytest.py
def stuff(a):
x=a
return x
Any suggestions where I might be going wrong?
回答1:
From the documentation:
PyObject* PyObject_CallObject(PyObject *callable, PyObject *args)
This is the equivalent of the Python expression: callable(*args).
Whereas PyObject_CallFunctionObjArgs
is documented as:
PyObject* PyObject_CallFunctionObjArgs(PyObject *callable, ..., NULL)
This is the equivalent of the Python expression: callable(arg1, arg2, ...).
So change your call to the following:
PyObject* result = PyObject_CallFunctionObjArgs(pFunc, list, NULL);
(or you could wrap your list inside another list and keep on using CallObject
, but this is by far the easier solution)
来源:https://stackoverflow.com/questions/60487083/passing-array-tuple-from-python-back-to-c