How to unmarshall an array of different types correctly?

问题

As long as I have key-value pairs unmarshalling is pretty straight forward but how would I unmarshall an array of different types in different order? The single elements are well defined and known but the order is not.

I can not come up with a beautiful solution.

Would I try and error over all elements? Is there some kind of union type that could do that for me?

playground version

package main

import (
    "encoding/json"
    "fmt"
)

var my_json string = `{
    "an_array":[
        "with_a string",
        {
            "and":"some_more",
            "different":["nested", "types"]
        }
    ]
}`

type MyInner struct {
    And     string
    Different   []string
}

type MyJSON struct {
    An_array []json.RawMessage
}

func main() {
    var my_json_test MyJSON

    e := json.Unmarshal([]byte(my_json), &my_json_test)
    if e != nil {
        fmt.Println(e)
    } else {
        for index, value := range my_json_test.An_array {
            fmt.Println("index: ", index)
            fmt.Println("value: ", string(value))
        }
        var my_inner MyInner
        err := json.Unmarshal(my_json_test.An_array[1], &my_inner)
        if err != nil {
            fmt.Println(err)
        } else {
            fmt.Println("inner structure: ", my_inner)
        }
    }
}

回答1:

Go official blog has a nice article about encoding/json: JSON and GO. It's possible to "Decode arbitrary data" into an interface{} and use type assertion to determine the type dynamically.

Your code can be probably modified to this:

package main

import (
    "encoding/json"
    "fmt"
)

var my_json string = `{
    "an_array":[
    "with_a string",
    {
        "and":"some_more",
        "different":["nested", "types"]
    }
    ]
}`

func WTHisThisJSON(f interface{}) {
    switch vf := f.(type) {
    case map[string]interface{}:
        fmt.Println("is a map:")
        for k, v := range vf {
            switch vv := v.(type) {
            case string:
                fmt.Printf("%v: is string - %q\n", k, vv)
            case int:
                fmt.Printf("%v: is int - %q\n", k, vv)
            default:
                fmt.Printf("%v: ", k)
                WTHisThisJSON(v)
            }

        }
    case []interface{}:
        fmt.Println("is an array:")
        for k, v := range vf {
            switch vv := v.(type) {
            case string:
                fmt.Printf("%v: is string - %q\n", k, vv)
            case int:
                fmt.Printf("%v: is int - %q\n", k, vv)
            default:
                fmt.Printf("%v: ", k)
                WTHisThisJSON(v)
            }

        }
    }
}

func main() {

    fmt.Println("JSON:\n", my_json, "\n")

    var f interface{}
    err := json.Unmarshal([]byte(my_json), &f)
    if err != nil {
        fmt.Println(err)
    } else {
        fmt.Printf("JSON: ")
        WTHisThisJSON(f)
    }
}

It gives output as follows:

JSON:
 {
    "an_array":[
    "with_a string",
    {
        "and":"some_more",
        "different":["nested", "types"]
    }
    ]
} 

JSON: is a map:
an_array: is an array:
0: is string - "with_a string"
1: is a map:
and: is string - "some_more"
different: is an array:
0: is string - "nested"
1: is string - "types"

It's not complete yet, but shows how it's gonna work.

来源：https://stackoverflow.com/questions/13364181/how-to-unmarshall-an-array-of-different-types-correctly

标签

json

unmarshalling