问题
I want to be able to store a class as a variable, so I can call class methods out of it later, something like this:
class SomeGenericItem: NSObject
{
var cellClass: AnyClass
init(cellClass: AnyClass)
{
self.cellClass = cellClass
}
func doSomething(p1: String, p2: String, p3: String)
{
self.cellClass.doSomething(p1, p2: p2, p3: p3)
}
}
class SomeClass: NSObject
{
class func doSomething(p1: String, p2: String, p3: String)
{
...
}
}
I want to be able to say something like:
let someGenericItem = SomeGenericItem(cellClass: SomeClass.self)
someGenericItem.doSomething("One", p2: "Two", p3: "Three")
What I'm trying to figure out is:
1) How would a protocol be defined so I could call class func doSomething?
2) What would the declaration of cellClass need to be?
3) What would the call look like?
回答1:
Protocols can't define class methods, but static methods are fine. You'll need your wrapper to be generic, and specify a 'where' constraint that guarantees the wrapped type's conformance to your protocol.
Example:
protocol FooProtocol
{
static func bar() -> Void
}
class FooishClass : FooProtocol
{
static func bar() -> Void
{
println( "FooishClass implements FooProtocol" )
}
}
class FooTypeWrapper< T where T: FooProtocol >
{
init( type: T.Type )
{
//no need to store type: it simply is T
}
func doBar() -> Void
{
T.bar()
}
}
Use:
let fooishTypeWrapper = FooTypeWrapper( type: FooishClass.self )
fooishTypeWrapper.doBar()
来源:https://stackoverflow.com/questions/29712667/pass-a-swift-class-as-parameter-and-then-call-a-class-method-out-of-it