问题
I have a list of products which should show variations in it's own row. The code for that works fine so far.
But I couldn't figure out how I could show the SKU of a variation.
Here's my current code:
$args = [
'status' => array('publish', 'draft'),
'orderby' => 'name',
'order' => 'ASC',
'limit' => -1,
];
$vendor_products = wc_get_products($args);
$list_array = array();
foreach ($vendor_products as $key => $product) {
if ($product->get_type() == "variable") {
foreach ($product->get_variation_attributes() as $variations) {
foreach ($variations as $variation) {
$list_array[] = array(
'SKU' => $product->get_sku(),
'Name' => $product->get_title() . " - " . $variation,
);
}
}
} else {
$list_array[] = array(
'SKU' => $product->get_sku(),
'Name' => $product->get_title(),
);
}
}
return $list_array;
I tried to display the product attributes and I also tried to get the ID of the variation. Nothing works for me?!
Is there no simple way to get the variation SKU?
回答1:
You should better use WC_Product_Variable
get_children() method like:
$args = [
'status' => array('publish', 'draft'),
'orderby' => 'name',
'order' => 'ASC',
'limit' => -1,
];
$vendor_products = wc_get_products($args);
$list_array = array();
foreach ($vendor_products as $key => $product) {
if ( $product->is_type( "variable" ) ) {
foreach ( $product->get_children( false ) as $child_id ) {
// get an instance of the WC_Variation_product Object
$variation = wc_get_product( $child_id );
if ( ! $variation || ! $variation->exists() ) {
continue;
}
$list_array[] = array(
'SKU' => $variation->get_sku(),
'Name' => $product->get_name() . " - " . $child_id,
);
}
} else {
$list_array[] = array(
'SKU' => $product->get_sku(),
'Name' => $product->get_name(),
);
}
}
return $list_array;
Or even some other available methods like get_available_variations() (which use get_children()
method when looking at its source code). It should better work...
Targeting product variations of a variable product with different other post statuses than "publish"
.
In this case you should replace get_children() method with a custom WP_Query that will handle other post statuses like below:
$statuses = array('publish', 'draft');
// Args on the main query for WC_Product_Query
$args = [
'status' => $statuses,
'orderby' => 'name',
'order' => 'ASC',
'limit' => -1,
];
$vendor_products = wc_get_products($args);
$list_array = array();
foreach ($vendor_products as $key => $product) {
if ($product->get_type() == "variable") {
// Args on product variations query for a variable product using a WP_Query
$args2 = array(
'post_parent' => $product->get_id(),
'post_type' => 'product_variation',
'orderby' => array( 'menu_order' => 'ASC', 'ID' => 'ASC' ),
'fields' => 'ids',
'post_status' => $statuses,
'numberposts' => -1,
);
foreach ( get_posts( $args2 ) as $child_id ) {
// get an instance of the WC_Variation_product Object
$variation = wc_get_product( $child_id );
if ( ! $variation || ! $variation->exists() ) {
continue;
}
$list_array[] = array(
'SKU' => $variation->get_sku(),
'Name' => $product->get_name() . " - " . $child_id,
);
}
} else {
$list_array[] = array(
'SKU' => $product->get_sku(),
'Name' => $product->get_name(),
);
}
}
return $list_array;
This time you will get all the product variations of your variable products.
For reference: Product -> Get Children doesn't return all variations #13469
来源:https://stackoverflow.com/questions/61097155/woocommerce-get-skus-of-all-product-variations