Adding another suffix to a path that already has a suffix with pathlib

问题

I was converting some old Python code to use pathlib instead of os.path for most path-related operations, but I ended up with the following problem: I needed to add another extension to a path that already had an extension (not replace it). With os.path, since we are merely manipulating strings, the solution was to add the extension with string operations:

newpath = path + '.res'

It doesn't work with pathlib.Path because it doesn't allow concatenation of arbitrary characters. The closest I could find was the following:

newpath = path.with_suffix(path.suffix + '.res')

It looks like a workaround because it still uses string addition in the end. And it has a new pitfall because I forgot at first to handle the case where there are already several extensions and you want to add a new one, leading to the following code to get back the old behaviour:

newpath = path.with_suffix(''.join(path.suffixes) + '.res')

Now it doesn't feel terse nor clean since it uses more and more string operations to achieve the old behaviour instead of pure path operations. The fact that Path.suffixes exists means that the library's developers considered the case where a file can have multiple extensions, yet I couldn't find a way to simply add a new extension to a path. Is there a more idiomatic way that I have missed to achieve the same behaviour?

EDIT: actually path.with_suffix(path.suffix + '.res') is enough to handle the case where there are already several file extensions, even though it wasn't immeditely obvious to me.

回答1:

It doesn't seem like Path's like being modified in-place (you can't change .parts[-1] directory or change .suffixes, etc.), but that doesn't mean you need to resort to anything too unsavory. The following works just fine, even if it's not quite as elegant as I'd like:

new_path = (path.parent / path.name).with_suffix(path.suffix + new_suffix)

where path is your original Path variable, and new_suffix is the string with your new suffix/extension (including the leading ".")

回答2:

You can just convert your Path to string then add new extension and convert back to Path:

from pathlib import Path
first = Path("D:/user/file.xy")
print(first)
second = Path(str(first)+".res")
print(second)

回答3:

I find the following slightly more satisfying than the answers that have already been given:

new_path = path.parent / (path.name + '.suffix')

回答4:

The following code should do what you want it to in a very dynamic way.

from pathlib import Path
import time

p = Path('.')
p = p / '..' / 'Python' / 'Files' / 'Texts_to_read' / 'a_text_file'

new_p = str(p).split('\\')

new_suffix = '.txt'

new_p[-1] = new_p[-1] + new_suffix

p = Path('.')

for x in new_p:
    p = p / x

print(new_p)

print(p)
print(str(p))

time.sleep(5)

The fact that normal string operations can be used in this case is a good thing, as it adds a great deal of control over the file path desired without requiring a large assortment of new functions.

来源：https://stackoverflow.com/questions/49380572/adding-another-suffix-to-a-path-that-already-has-a-suffix-with-pathlib