问题
Basically I have been working on a simple chat room using socket and thread. In my client I can receive and send messages, my issue is that one comes before another in a loop, so if I am sending a message I will only receive data once I have sent a message. I want it to work like any other chat room, where I could receive a message when I am sending a message, any help will help greatly. This is my basic client:
import socket
import sys
###########
HOST = '25.0.18.52'
PORT = 9999
###########
name = input("Enter your name: ")
s = socket.socket()
s.connect((HOST,PORT))
while 1:
message = input("Message: ")
s.send("{}: {}".format(name, message).encode('utf-8'))
data = s.recv(1024)
a = data.decode("utf-8")
print(a)
回答1:
You should keep 2 threads: one for listening and the other for receiving. In your while
loop, you should remove the listener part, and keep the code in a different thread. This way you can receive and type on the console at the same time.
def recv():
while True:
data = s.recv(1024).decode()
if not data: sys.exit(0)
print data
Thread(target=recv).start()
来源:https://stackoverflow.com/questions/33434007/python-socket-send-receive-messages-at-the-same-time