问题
I am working with Selenium Standalone Server 3.0.1
. I am trying to add an Explicit Wait
to my code to detect an element through xpath when the element becomes visible. In order to get some Java help I looked out for the source code for Selenium Standalone Server 3.0.1
but was unable to find it. I found the source code in selenium-java-2.53.1
release. I downloaded it and found selenium-java-2.53.1-srcs
and added to my Eclipse IDE
. From the help of FluentWait
, I simply copy pasted the code in my Eclipse IDE
and changed the variable names.
The sample code in documentation is like:
// Waiting 30 seconds for an element to be present on the page, checking
// for its presence once every 5 seconds.
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(30, SECONDS)
.pollingEvery(5, SECONDS)
.ignoring(NoSuchElementException.class);
WebElement foo = wait.until(new Function<WebDriver, WebElement>() {
public WebElement apply(WebDriver driver) {
return driver.findElement(By.id(\"foo\"));
}
});
But when I implement this code, simply copy pasting it:
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(30, TimeUnit.SECONDS)
.pollingEvery(5, TimeUnit.SECONDS)
.ignoring(NoSuchElementException.class);
WebElement element = wait.until(new Function<WebDriver, WebElement>() {
public WebElement apply(WebDriver driver) {
return driver.findElement(By.xpath(\"//p[text()=\'WebDriver\']\"));
}
});
I am getting an error on FluentWait
Class as The type FluentWait is not generic; it cannot be parameterized with arguments <WebDriver>
Here is the list of my imports:
import java.util.concurrent.TimeUnit;
import org.apache.log4j.Logger;
import org.apache.log4j.PropertyConfigurator;
import org.openqa.selenium.By;
import org.openqa.selenium.NoSuchElementException;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.openqa.selenium.support.ui.Wait;
import com.google.common.base.Function;
Can anyone help me out please?
Update
Added an answer with respect to the modified constructor of FluentWait in Selenium v3.11.0
回答1:
You need to specify expected condition inside the wait below is the modified code that could solve your problem.
Code:
import java.util.concurrent.TimeUnit;
import org.junit.Test;
import org.openqa.selenium.By;
import org.openqa.selenium.NoSuchElementException;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.FluentWait;
import org.openqa.selenium.support.ui.Wait;
public class DummyClass
{
WebDriver driver;
@Test
public void test()
{
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(30, TimeUnit.SECONDS)
.pollingEvery(5, TimeUnit.SECONDS)
.ignoring(NoSuchElementException.class);
until(new Function<WebElement, Boolean>()
{
public Boolean apply(WebElement element)
{
return element.getText().endsWith("04");
}
private void until(Function<WebElement, Boolean> function)
{
driver.findElement(By.linkText("Sample Post2"));
}
}
}
}
回答2:
With the availability of Selenium v3.11.0 the constructor of FluentWait have changed. Now the argument type for withTimeout and pollingEvery is Duration. Here is the modified implementation :
import java.time.Duration;
import org.openqa.selenium.By;
import org.openqa.selenium.NoSuchElementException;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
import org.openqa.selenium.support.ui.FluentWait;
import org.openqa.selenium.support.ui.Wait;
import com.google.common.base.Function;
public class Fluent_Wait {
public static void main(String[] args) {
System.setProperty("webdriver.gecko.driver", "C:\\Utility\\BrowserDrivers\\geckodriver.exe");
WebDriver driver = new FirefoxDriver();
driver.get("https://www.google.com");
// Waiting 30 seconds for an element to be present on the page, checking
// for its presence once every 500 milliseconds.
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(Duration.ofSeconds(30))
.pollingEvery(Duration.ofMillis(500))
.ignoring(NoSuchElementException.class);
WebElement foo = wait.until(new Function<WebDriver, WebElement>() {
public WebElement apply(WebDriver driver) {
return driver.findElement(By.name("q"));
}
});
}
}
回答3:
The simplest solution is to use the other method implementation:
withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
The form withTimeout(Duration timeOut)
is still used and non-deprecated one
来源:https://stackoverflow.com/questions/42275658/the-type-fluentwait-is-not-generic-it-cannot-be-parameterized-with-arguments-w