Converting preg_replace to preg_replace_callback for finding and replacing words with variables

问题

I have the following line of code:

$message = preg_replace('/\{\{([a-zA-Z_-]+)\}\}/e', "$$1", $body);

This replaces words surrounded by two curly brackets with variables of the same name. ie {{username}} gets replaced by $username.

I am trying to convert it to use preg_replace_callback. This is my code so far based on Googling, but I'm not really sure what I am doing! The error_log output is showing the variable name including the curly brackets.

$message = preg_replace_callback(
    "/\{\{([a-zA-Z_-]+)\}\}/",
        function($match){
            error_log($match[0]);
            return $$match[0];
        },
        $body
);

Any help greatly appreciated.

回答1:

Functions have their own variable scope in PHP, so anything you're trying to replace isn't available inside the function unless you make it explicitly so. I'd recommend putting your replacements in an array instead of individual variables. This has two advantages -- first, it allows you to easily get them inside the function scope and second, it provides a built-in whitelisting mechanism so that your templates can't accidentally (or intentionally) refer to variables that shouldn't be exposed.

// Don't do this:
$foo = 'FOO';
$bar = 'BAR';

// Instead do this:
$replacements = [
    'foo' => 'FOO',
    'bar' => 'BAR',
];

// Now, only things inside the $replacements array can be replaced.

$template = 'this {{foo}} is a {{bar}} and here is {{baz}}';
$message = preg_replace_callback(
    '/\{\{([a-zA-Z_-]+)\}\}/',
    function($match) use ($replacements) {
        return $replacements[$match[1]] ?? '__ERROR__';
    },
    $template
);

echo "$message\n";

This yields:

this FOO is a BAR and here is __ERROR__

来源：https://stackoverflow.com/questions/53873707/converting-preg-replace-to-preg-replace-callback-for-finding-and-replacing-words

标签

php

regex

preg-replace

preg-replace-callback