Incrementing integer variable of global scope in Python [duplicate]

问题

This question already has answers here:

How do I pass a variable by reference? (26 answers)

Closed 4 years ago.

I am trying to change global value x from within another functions scope as the following code shows,

x = 1
def add_one(x):
    x += 1

then I execute the sequence of statements on Python's interactive terminal as follows.

>>> x
1
>>> x += 1
>>> x
2
>>> add_one(x)
>>> x
2

Why is x still 2 and not 3?

回答1:

Because x is a local (all function arguments are), not a global, and integers are not mutable.

So x += 1 is the same as x = x + 1, producing a new integer object, and x is rebound to that.

You can mark x a global in the function:

def add_one():
    global x
    x += 1

There is no point in passing in x as an argument here.

来源：https://stackoverflow.com/questions/30964478/incrementing-integer-variable-of-global-scope-in-python