编写一个程序,开启 3 个线程,这三个线程的 ID 分别为 A、B、C,
每个线程将自己的 ID 在屏幕上打印 10 遍,要 求输出的结果必须按顺序显示
TestABCAlternate
package com.aff.juc; import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock; public class TestABCAlternate { public static void main(String[] args) { AlternateDemo ad = new AlternateDemo(); new Thread(new Runnable() { @Override public void run() { for (int i = 1; i <= 20; i++) { ad.loopA(i); } } },"A线程").start(); new Thread(new Runnable() { @Override public void run() { for (int i = 1; i <= 20; i++) { ad.loopB(i); } } },"B线程").start(); new Thread(new Runnable() { @Override public void run() { for (int i = 1; i <=20; i++) { ad.loopC(i); System.out.println("============================="); } } },"C线程").start(); } } class AlternateDemo { private int number = 1; private Lock lock = new ReentrantLock(); private Condition condition1 = lock.newCondition(); private Condition condition2 = lock.newCondition(); private Condition condition3 = lock.newCondition(); // totalLoop :循环几轮 public void loopA(int totalLoop) { lock.lock(); try { // 1. 判断 if (number != 1) { condition1.await(); } // 2.打印 for (int i = 1; i <= 2; i++) { System.out.println(Thread.currentThread().getName() + "\t" + i +"\t"+ "\t" + totalLoop); } // 3.唤醒 number = 2; condition2.signal();// number为2 唤醒condition2 } catch (Exception e) { e.printStackTrace(); } finally { lock.unlock(); } } public void loopB(int totalLoop) { lock.lock(); try { // 1. 判断 if (number != 2) { condition2.await(); } // 2.打印 for (int i = 1; i <= 2; i++) { System.out.println(Thread.currentThread().getName() + "\t" + "\t"+ i + "\t" + totalLoop); } // 3.唤醒 number = 3; condition3.signal();// number为3 唤醒condition3 } catch (Exception e) { e.printStackTrace(); } finally { lock.unlock(); } } public void loopC(int totalLoop) { lock.lock(); try { // 1. 判断 if (number != 3) { condition3.await(); } // 2.打印 for (int i = 1; i <= 2; i++) { System.out.println(Thread.currentThread().getName() + "\t" + "\t"+ i + "\t" + totalLoop); } // 3.唤醒 number = 1; condition1.signal();// number为1 唤醒condition1 } catch (Exception e) { e.printStackTrace(); } finally { lock.unlock(); } } }
来源:https://www.cnblogs.com/afangfang/p/12632559.html