EXCEL vba工程密码破解

方法一:
这种方法实际是避开VBA工程密码验证，即骗vba编辑器，该密码输入成功，请求放行。
不管他是破解还是欺骗能达到我们的目的角开就行
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1.新建一个工作簿，打开，按ALT+F11，进入vba代码编辑器窗口：
2.新建一个模块，“插入”--“模块”把以下代码复制进模块并保存

ption Explicit
Private Declare Sub MoveMemory Lib "kernel32" Alias "RtlMoveMemory" _
        (Destination As Long, Source As Long, ByVal Length As Long)


Private Declare Function VirtualProtect Lib "kernel32" (lpAddress As Long, _
        ByVal dwSize As Long, ByVal flNewProtect As Long, lpflOldProtect As Long) As Long
        
Private Declare Function GetModuleHandleA Lib "kernel32" (ByVal lpModuleName As String) As Long
   
Private Declare Function GetProcAddress Lib "kernel32" (ByVal hModule As Long, _
        ByVal lpProcName As String) As Long
   
Private Declare Function DialogBoxParam Lib "user32" Alias "DialogBoxParamA" (ByVal hInstance As Long, _
        ByVal pTemplateName As Long, ByVal hWndParent As Long, _
        ByVal lpDialogFunc As Long, ByVal dwInitParam As Long) As Integer
        
Dim HookBytes(0 To 5) As Byte
Dim OriginBytes(0 To 5) As Byte
Dim pFunc As Long
Dim Flag As Boolean


Private Function GetPtr(ByVal Value As Long) As Long
    '获得函数的地址
    GetPtr = Value
End Function


Public Sub RecoverBytes()
    '若已经hook,则恢复原API开头的6字节,也就是恢复原来函数的功能
    If Flag Then MoveMemory ByVal pFunc, ByVal VarPtr(OriginBytes(0)), 6
End Sub


Public Function Hook() As Boolean
    Dim TmpBytes(0 To 5) As Byte
    Dim p As Long
    Dim OriginProtect As Long
   
    Hook = False
   
    'VBE6.dll调用DialogBoxParamA显示VB6INTL.dll资源中的第4070号对话框(就是输入密码的窗口)
    '若DialogBoxParamA返回值非0,则VBE会认为密码正确,所以我们要hook DialogBoxParamA函数
    pFunc = GetProcAddress(GetModuleHandleA("user32.dll"), "DialogBoxParamA")
   
    '标准api hook过程之一: 修改内存属性,使其可写
    If VirtualProtect(ByVal pFunc, 6, &H40, OriginProtect) <> 0 Then
        '标准api hook过程之二: 判断是否已经hook,看看API的第一个字节是否为&H68,
        '若是则说明已经Hook
        MoveMemory ByVal VarPtr(TmpBytes(0)), ByVal pFunc, 6
        If TmpBytes(0) <> &H68 Then
            '标准api hook过程之三: 保存原函数开头字节,这里是6个字节,以备后面恢复
            MoveMemory ByVal VarPtr(OriginBytes(0)), ByVal pFunc, 6
            '用AddressOf获取MyDialogBoxParam的地址
            '因为语法不允许写成p = AddressOf MyDialogBoxParam,这里我们写一个函数
            'GetPtr,作用仅仅是返回AddressOf MyDialogBoxParam的值,从而实现将
            'MyDialogBoxParam的地址付给p的目的
            p = GetPtr(AddressOf MyDialogBoxParam)
            
            '标准api hook过程之四: 组装API入口的新代码
            'HookBytes 组成如下汇编
            'push MyDialogBoxParam的地址
            'ret
            '作用是跳转到MyDialogBoxParam函数
            HookBytes(0) = &H68
            MoveMemory ByVal VarPtr(HookBytes(1)), ByVal VarPtr(p), 4
            HookBytes(5) = &HC3
            
            '标准api hook过程之五: 用HookBytes的内容改写API前6个字节
            MoveMemory ByVal pFunc, ByVal VarPtr(HookBytes(0)), 6
            '设置hook成功标志
            Flag = True
            Hook = True
        End If
    End If
End Function

Private Function MyDialogBoxParam(ByVal hInstance As Long, _
        ByVal pTemplateName As Long, ByVal hWndParent As Long, _
        ByVal lpDialogFunc As Long, ByVal dwInitParam As Long) As Integer
    If pTemplateName = 4070 Then
        '有程序调用DialogBoxParamA装入4070号对话框,这里我们直接返回1,让
        'VBE以为密码正确了
        MyDialogBoxParam = 1
    Else
        '有程序调用DialogBoxParamA,但装入的不是4070号对话框,这里我们调用
        'RecoverBytes函数恢复原来函数的功能,在进行原来的函数
        RecoverBytes
        MyDialogBoxParam = DialogBoxParam(hInstance, pTemplateName, _
                           hWndParent, lpDialogFunc, dwInitParam)
        '原来的函数执行完毕,再次hook
        Hook
    End If
End Function

View Code

3.右击sheet1工作表，“查看代码”复制以下代码进去并保存：

sub 破解()
if hook then
msgbox "破解成功"
end if
end sub


sub 恢复()
RecoverBytes
msgbox "恢复成功"
end sub

4.到此,一个vba破解程序完成了,回到该工作簿窗口,文件-打开打开需要破解vba工程密码的工作簿.
5.运行"call 破解" 稍后你再双击刚才要解密的VBA工程窗体.是不是如入无人之境啊,工程保护密码形同虚设啊?
6.破解完成后,请右键刚破解的VBA工程,在"查看工程时需要密码"的地方复选框取消选择,OK.完成.
7.完成后别忘了执行"call 恢复",恢复密码保护(恢复程序的密码保护,已被破解的文件不收影响. (请勿用于非法途径)

已验证，破解成功

方法二:

新建一个Excel工作簿,Alt+F11 打开VBA编辑器,新建一个模块 ,复制以下代码,注意如提示变量未定义,则把Option Explicit行删除即可,经测试已经通过.
 
'移除VBA编码保护
Sub MoveProtect()
    Dim FileName As String
    FileName = Application.GetOpenFilename("Excel文件（*.xls & *.xla）,*.xls;*.xla", , "VBA破解")
    If FileName = CStr(False) Then
       Exit Sub
    Else
       VBAPassword FileName, False
    End If
End Sub
 
'设置VBA编码保护
Sub SetProtect()
    Dim FileName As String
    FileName = Application.GetOpenFilename("Excel文件（*.xls & *.xla）,*.xls;*.xla", , "VBA破解")
    If FileName = CStr(False) Then
       Exit Sub
    Else
       VBAPassword FileName, True
    End If
End Sub
 
Private Function VBAPassword(FileName As String, Optional Protect As Boolean = False)
      If Dir(FileName) = "" Then
         Exit Function
      Else
         FileCopy FileName, FileName & ".bak"
      End If
 
      Dim GetData As String * 5
      Open FileName For Binary As #1
      Dim CMGs As Long
      Dim DPBo As Long
      For i = 1 To LOF(1)
          Get #1, i, GetData
          If GetData = "CMG=""" Then CMGs = i
          If GetData = "[Host" Then DPBo = i - 2: Exit For
      Next
      If CMGs = 0 Then
         MsgBox "请先对VBA编码设置一个保护密码...", 32, "提示"
         Exit Function
      End If
      If Protect = False Then
         Dim St As String * 2
         Dim s20 As String * 1
         '取得一个0D0A十六进制字串
         Get #1, CMGs - 2, St
         '取得一个20十六制字串
         Get #1, DPBo + 16, s20
         '替换加密部份机码
         For i = CMGs To DPBo Step 2
             Put #1, i, St
         Next
         '加入不配对符号
         If (DPBo - CMGs) Mod 2 <> 0 Then
            Put #1, DPBo + 1, s20
         End If
         MsgBox "文件解密成功......", 32, "提示"
      Else
         Dim MMs As String * 5
         MMs = "DPB="""
         Put #1, CMGs, MMs
         MsgBox "对文件特殊加密成功......", 32, "提示"
      End If
      Close #1
End Function

来源：https://www.cnblogs.com/Summer6/p/11245383.html

标签

vba

string

msgbox

dim

sub

vba工程密码清除

方法二: