问题
So I recently came across something like this
unsigned char ch : 7;
inside a struct. I read about it a little. Apparently these are called bit fields. They are used to set the width of data that a char can receive. But how do we use these things. For example, I know that we can set variable ch to be a byte
unsigned char ch = 0x61;
cout << ch << endl;
This will output
a
However, what do we do with the bitfields?
unsigned char ch : 7;
ch = 0x61; //This doesn't work for some reason
unsigned char ch : 7;
unsigned char ch = 0x61/ //Neither does this.
Thanks for the help
回答1:
Bitfields can only be used inside structured data types, i.e. struct
, class
, and union
types. The purpose is to allow you to pack multiple members inside a single byte, without having to write lots of explicit shifts and masks. For instance, you can write:
struct halfbyte_t {
unsigned int half1: 4;
unsigned int half2: 4;
} halfbyte;
This declares a variable named halfbyte
that contains two 4-bit members, which will be packed into a single 8-bit byte, rather than having to use 2 bytes if you just declared them unsigned char
.
You access them just like any other structure member:
halfbyte.half1 = 3;
cout << halfbyte.half3;
1-bit fields are especially useful if you have lots of boolean flags in a structure, since you don't have to have a separate byte for each flag.
struct flag_t {
unsigned int flag1: 1;
unsigned int flag2: 1;
unsigned int flag3: 1;
unsigned int flag4: 1;
...
};
来源:https://stackoverflow.com/questions/35857111/c-how-to-use-bitfields