问题
I am trying to write a macro for logging mechanism. I wrote a variadic macro but it does not work with std::string
. The code looks like the following:
#include <stdio.h>
#include <string>
#define LOG_NOTE(m, ...) printf(m, ##__VA_ARGS__)
int main()
{
std::string foo = "random string";
int bar = 5;
LOG_NOTE("%s %d %s", "Hello World", bar, foo);
return 0;
}
If I would call the macro like following, I would not get any error.
LOG_NOTE("%s %d %s", "Hello World", bar, "random string");
Compiler Output:
In function 'int main()': 5:49: error: cannot pass objects of non-trivially-copyable type 'std::string {aka class std::basic_string}' through '...' 11:5: note: in expansion of macro 'LOG_NOTE'
回答1:
I wrote a variadic macro
Don't. Use a variadic template function.
The actual problem you have is that you're trying to pass a C++ object (std::string
) through a C API (printf
). This is not possible.
You'd need some mechanism for conversion, for example:
#include <stdio.h>
#include <string>
template<class T>
decltype(auto) convert_for_log_note(T const& x)
{
return x;
}
decltype(auto) convert_for_log_note(std::string const& x)
{
return x.c_str();
}
template<class...Args>
void LOG_NOTE(const char* format, Args&&...args)
{
printf(format, convert_for_log_note(args)...);
}
int main()
{
std::string foo = "random string";
int bar = 5;
LOG_NOTE("%s %d %s\n", "Hello World", bar, foo);
return 0;
}
Example output:
Hello World 5 random string
http://coliru.stacked-crooked.com/a/beb3431114833860
Update:
For C++11 you'll need to spell out the return types by hand:
#include <stdio.h>
#include <string>
template<class T>
T const& convert_for_log_note(T const& x)
{
return x;
}
const char* convert_for_log_note(std::string const& x)
{
return x.c_str();
}
template<class...Args>
void LOG_NOTE(const char* format, Args&&...args)
{
printf(format, convert_for_log_note(args)...);
}
int main()
{
std::string foo = "random string";
int bar = 5;
LOG_NOTE("%s %d %s\n", "Hello World", bar, foo);
return 0;
}
回答2:
The issue here is not the variadic macro, but the call to printf
. Have a look at the documentation: the format specifier "%s"
corresponds to char*
, not std::string
. printf
can only handle primitive builtin types. You can change you invocation to
LOG_NOTE("%s %d %s", "Hello World", bar, foo.c_str());
to fix this.
回答3:
You cannot pass object to printf
, so you have currently to use
LOG_NOTE("%s %d %s", "Hello World", bar, foo.c_str());
If you don't need formatting, and just write every argument separated with space, you might simply use variadic template instead of MACRO:
template <typename ... Ts>
void LOG_NOTE(const Ts&...args)
{
const char* sep = "";
(((std::cout << sep << args), sep = " "), ...); // C++17 folding expression
// C++11/C++14 version are more verbose:
// int dummy[] = {0, ((std::cout << sep << args), (sep = " "), 0)...};
// static_cast<void>(dummy); // avoid warning for unused variable
}
int main()
{
std::string foo = "random string";
int bar = 5;
LOG_NOTE("Hello World", bar, foo);
}
Demo
回答4:
I could not get @richardhodges nice solution to work in any of the C++11 compilers I tried. However, the following works with gcc -std=c++11
:
#include <stdio.h>
#include <string>
template<class T>
T convert_for_log_note(T const& x)
{
return x;
}
inline const char* convert_for_log_note(std::string const& x)
{
return x.c_str();
}
template<class...Args>
void LOG_NOTE(const char* format, Args&&...args)
{
printf(format, convert_for_log_note(args)...);
}
int main()
{
std::string foo = "random string";
int bar = 5;
LOG_NOTE("%s %d %s\n", "Hello World", bar, foo);
return 0;
}
The inline
keyword is necessary with the above solution for the Arduino C++ compiler, whereas other g++ compilers do not require it (the ones I have tried, anyways). Without this keyword, the Arduino code compiles, but the linker complains about multiple definitions.
来源:https://stackoverflow.com/questions/51856415/variadic-macro-cannot-pass-objects-of-non-trivially-copyable-type-through