问题
Quite new to this so I hope I have the terminology in the title right.
I am trying to figure out how to create an instance method that will do the following:
--An ID number is returned.
--As each object is created from the class constructor(instantiated?), a unique integer ID number is assigned to it. The first ID number is 1, and as new objects are instantiated, successive numbers will be assigned.
I am able to find examples of class/static methods that do the above however I am unable to figure out how to do this with an instance method. My attempt is below:
class Coordinates
{
private int iD = 0;
private float xCoordinate;
private float yCoordinate;
public Coordinates()
{
//Asks for input and assigns it to the two variables below
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter the X Coordinate followed by the return key");
xCoordinate = keyboard.nextDouble();
System.out.println("Please enter the Y Coordinate followed by the return key");
yCoordinate = keyboard.nextDouble();
iD++;
}
public getiD()
{
return iD;
}
}
My main method is as follows:
public class Machine
{
public static void main(String[] args)
{
Coordinates c1 = new Coordiantes();
Coordinates c2 = new Coordiantes();
Coordinates c3 = new Coordiantes();
System.out.println("ID: " + c1.getID());
System.out.println("ID: " + c2.getID());
System.out.println("ID: " + c3.getID());
}
}
Please note I have not included my entire code for the sake of simplicity and easiness to follow. I hope I have added enough.
I also don't want to use java.util.UUID.
回答1:
The problem right now is that your 'id' is an instance variable, meaning it belong to the objects you create. Think of it that every time you create an object a new and fresh copy of your instance variable is made. So every time you create an object the id is first set to 0, then post incremented once (thus all objects have an id=0).
If you want to create a variable that, say, automatically counts all objects you have created in a class or has the id, you need to make a class variable. These variable belong to all the objects you create from a class and the keyword used for that is 'static'.
Note: I have used a static variable BUT not a static method. If you don't want to use static at all, it is a different question
class Coordinates
{
private static int count = 0;
private int id=0;
private float xCoordinate;
private float yCoordinate;
public Coordinates()
{
//Asks for input and assigns it to the two variables below
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter the X Coordinate followed by the return key");
xCoordinate = keyboard.nextDouble();
System.out.println("Please enter the Y Coordinate followed by the return key");
yCoordinate = keyboard.nextDouble();
id=count++;
}
public getiD()
{
return iD;
}
}
A simple change of keyword will make your program correct. You dont have to do too much complicated stuff.
It is difficult to grasp the concept of class and objects, static and instance variables at first. Let me know if you'd like more explanation :)
回答2:
Maintaining an ID sequence is a separate responsibility from the rest of what your object does, and doesn't belong to any one instance of the Coordinates class, so it belongs in a different object. Make a separate object to maintain the sequence and hand out numbers, something like
public class MySequence {
private AtomicLong currentValue = new AtomicLong(0L);
public long getNextValue() {
return currentValue.getAndIncrement();
}
}
then use that sequence to initialize your objects:
new CoordinatePair(mySequence.getNextValue(), x, y);
By the way keeping user input separate from the model makes things simpler, you may want to instantiate your Coordinates class in cases where the input doesn't come from the user. Console input doesn't go in a constructor. You might have a Coordinate class like
public CoordinatePoint {
private long id;
private float x;
private float y;
public CoordinatePoint(long id, float x, float y) {
this.id = id;
this.x = x;
this.y = y;
}
public String toString() {
return "id=" + id + ", (" + x + ", " + y + ")";
}
}
and a main method like
public class Example {
public static void main(String ... args) {
MySequence seq = new MySequence();
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter the X Coordinate followed by the return key");
float xCoordinate = keyboard.nextDouble();
System.out.println("Please enter the Y Coordinate followed by the return key");
float yCoordinate = keyboard.nextDouble();
CoordinatePoint c1 = new CoordinatePoint(seq.getNextValue(), xCoordinate, yCoordinate);
System.out.println(c1.toString());
}
}
回答3:
In the context of your current code, the simplest thing to to do is as below:
import java.util.concurrent.atomic.AtomicInteger;
public class Coordinates {
//static id generator shared among all instances of Coordinates
private static final AtomicInteger idGenerator = new AtomicInteger(1000);
private final Integer id;
public Coordinates() {
//assign unique id to an instance variable
id = idGenerator.getAndIncrement();
}
public int getId() {
//return instance variable
return id;
}
}
Test
public class Test {
public static void main(String[] args) {
for(int i = 0; i < 10; ++ i){
System.out.println(new CoordinatePoint().getId());
}
}
}
Output
1000 1001 1002 1003 1004 1005 1006 1007 1008 1009
回答4:
You can either make that ID static, or you could just make a Parent class called "Coordinate" (with that ID again being static) with "Point" children, and increment the ID in the constructor of each "Point" object.
Static would seem like the way to go.
来源：https://stackoverflow.com/questions/35461651/java-create-a-unique-id-for-each-instantiated-object-using-instance-methods-inst