问题
I am not interested in what the current UTC time is in milliseconds, nor do I need to mess with timezones. My original date is already stored as a UTC timestamp.
I have a date stored in a database in UTC time, "2012-06-14 05:01:25". I am not interested in the datetime, but just the date portion of the it. So, after retrieving the date in Java, and excluding the hours, minutes, and seconds - I am left with "2012-06-14".
How can I convert this into UTC milliseconds?
回答1:
EDIT: I'd missed the "ignoring the time of day" part. It's now present, but near the end...
The simplest approach is probably to use SimpleDateFormat, having set the time zone appropriately:
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
format.setTimeZone(TimeZone.getTimeZone("UTC"));
Date date = format.parse(text);
long millis = date.getTime();
(Setting the time zone is the important bit here, as otherwise it will interpret the value to be in the local time zone.)
Alternatively, if you're doing anything less trivial than this, use Joda Time which is a much better date/time API. In particular, SimpleDateFormat isn't thread-safe whereas DateTimeFormatter is:
// This can be reused freely across threads after construction.
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss")
.withLocale(Locale.US)
.withZoneUTC();
// Option 1
DateTime datetime = formatter.parseDateTime(text);
long millis = dateTime.getMillis();
// Option 2, more direct, but harder to diagnose errors
long millis = formatter.parseMillis(text);
Now so far, we've parsed the whole whole caboodle. The easiest way of ignoring the date part is just to round it off - after all, Java doesn't observe leap seconds, so we can just truncate it:
long millisPerDay = 24L * 60L * 60L * 1000L; // Or use TimeUnit
long dayMillis = (millis / millisPerDay) * millisPerDay;
That will "round towards 1970" so if you have a date before 1970 it will round to the end of the day - but I suspect that's unlikely to be a problem.
With the Joda Time version you could just use this instead:
DateTime dateTime = formatter.parseDateTime(text);
long millis = dateTime.toLocalDate().getLocalMillis();
I would personally not go with the idea of just taking a substring. Even though you're not actually interested in preserving the hour/minute/second, I think it's appropriate to parse what you've been given and then throw away information. Aside from anything else, it makes your code fail appropriately with bad data, e.g.
"2012-06-100"
or
"2012-06-14 25:01:25"
indicate problems in whatever's supplying you data, and it's good to spot that rather than to continue blindly just because the first 10 characters are okay.
回答2:
Simpler
The answer by Jon Skeet is correct. And he makes a good point about including, rather than truncating, the time-of-day info while parsing.
However, his code could be simplified. Especially so because Joda-Time gained an important new method in the latest versions: withTimeAtStartOfDay. This method supplants all the "midnight"-related classes and methods which are now deprecated.
Specifying a Locale is a good habit, as shown in his code. But in this particular case a Locale is not necessary.
His answer correctly suggests the Joda-Time library, far superior to using java.util.Date, .Calendar, and java.text.SimpleTextFormat. Those classes are notoriously troublesome, and should be avoided. Instead use either Joda-Time or the new java.time package built into Java 8 (inspired by Joda-Time, defined by JSR 310).
First Moment Of The Day
You cannot ignore time-of-day if what you want is a count of milliseconds-since-epoch. I suspect what you want is to change the time to first moment of the day. In UTC, this always means the time 00:00:00.000. But note that in local time zones, the first moment may be a different time because of Daylight Saving Time and possibly other anomalies.
ISO 8601
Your string is nearly in standard ISO 8601 format, but we need to swap a T for the SPACE in the middle. Then we can feed the resulting string directly to Joda-Time as Joda-Time has built-in formatters used by default for standard strings.
Example Code
The following example code assumes the intent of your question is to parse a string as a date-time value in UTC time zone, adjust the time to the first moment of the day, and then convert to number of milliseconds since Unix epoch (beginning of 1970 in UTC).
String inputRaw = "2012-06-14 05:01:25";
String input = inputRaw.replace( " ", "T" ); // Replace SPACE with a 'T'.
DateTime dateTime = new DateTime( input, DateTimeZone.UTC ); // Parse, assuming UTC.
DateTime dateTimeTopOfTheDay = dateTime.withTimeAtStartOfDay(); // Adjust to first moment of the day.
long millisecondsSinceUnixEpoch = dateTimeTopOfTheDay.getMillis(); // Convert to millis. Use a 'long', not an 'int'.
回答3:
Use the Date object in combination with SimpleDateFormat.
There is a method named getTime() in Date which will return the milliseconds for you.
Example that solves your problem :
Date truc = new SimpleDateFormat( "y-m-d").parse( "2010-06-14");
System.out.println(truc.getTime());
回答4:
SimpleDateFormat ft = new SimpleDateFormat ("yyyy-MM-dd"); //or whatever format you have
Date t = ft.parse('2014-03-20');
String result = String.format("%tQ", t);
System.out.printf("%tQ", t);
There are two methods here:
- you put the result milliseconds into a variable result
- printing it straight off.
回答5:
I use a simple and straight forward approach:
Date date = new Date(utcDateInString);
long utcDateInMilliSeconds = date.getTime();
来源：https://stackoverflow.com/questions/12081417/convert-utc-date-into-milliseconds