OpenCV 2 Centroid | 易学教程

问题

I am trying to find the centroid of a contour but am having trouble implementing the example code in C++ (OpenCV 2.3.1). Can anyone help me out?

回答1:

To find the centroid of a contour, you can use the method of moments. And functions are implemented OpenCV.

Check out these moments function (central and spatial moments).

Below code is taken from OpenCV 2.3 docs tutorial. Full code here.

/// Find contours
findContours( canny_output, contours, hierarchy, CV_RETR_TREE, CV_CHAIN_APPROX_SIMPLE, Point(0, 0) );

/// Get the moments
vector<Moments> mu(contours.size() );
for( int i = 0; i < contours.size(); i++ )
 { mu[i] = moments( contours[i], false ); }

///  Get the mass centers:
vector<Point2f> mc( contours.size() );
for( int i = 0; i < contours.size(); i++ )
 { mc[i] = Point2f( mu[i].m10/mu[i].m00 , mu[i].m01/mu[i].m00 ); }

Also check out this SOF, although it is in Python, it would be useful. It finds all parameters of a contour.

回答2:

If you have the mask of the contour area, you can find the centroid location as follows:

cv::Point computeCentroid(const cv::Mat &mask) {
    cv::Moments m = moments(mask, true);
    cv::Point center(m.m10/m.m00, m.m01/m.m00);
    return center;
}

This approach is useful when one has the mask but not the contour. In that case the above method is computationally more efficient vs. using cv::findContours(...) and then finding mass center.

Here's the source

回答3:

You can also use the following algorithms to find a centroid:

sumX = 0; sumY = 0;
size = array_points.size;
if(size > 0){

    foreach(point in array_points){
        sumX += point.x;
        sumY += point.y;
    }

 centroid.x = sumX/size;
 centroid.y = sumY/size;
}

Or with the help of Opencv's boundingRect:

//pseudo-code:

Rect bRect = Imgproc.boundingRect(array_points);

centroid.x = bRect.x + (bRect.width / 2);
centroid.y = bRect.y + (bRect.height / 2);

回答4:

Given the contour points, and the formula from Wikipedia, the centroid can be efficiently computed like this:

template <typename T> 
cv::Point_<T> computeCentroid(const std::vector<cv::Point_<T> >& in) {
    if (in.size() > 2) {
         T doubleArea = 0;
         cv::Point_<T> p(0,0);
         cv::Point_<T> p0 = in->back();
         for (const cv::Point_<T>& p1 : in) {//C++11
             T a = p0.x * p1.y - p0.y * p1.x; //cross product, (signed) double area of triangle of vertices (origin,p0,p1)
             p += (p0 + p1) * a;
             doubleArea += a;
             p0 = p1;
         }

         if (doubleArea != 0)
             return p * (1 / (3 * doubleArea) ); //Operator / does not exist for cv::Point
    }

    ///If we get here,
    ///All points lies on one line, you can compute a fallback value,
    ///e.g. the average of the input vertices
    [...]
}

Note:

This formula works with vertices given both in clockwise and counterclockwise order.
If the points have integer coordinates, it might be convenient to adapt the type of p and of the return value to Point2f or Point2d, and to add a cast to float or double to the denominator in the return statement.

来源：https://stackoverflow.com/questions/9074202/opencv-2-centroid

标签

c++

OpenCV

image-processing

centroid