二分法在循环有序数组查找元素

//在 O(logN) 时间内，从循环有序数组里查找元素

//二分之后，总有一半是有序数组

public static int searchInLoopSortedArray(int[] nums, int target) {
    if(nums.length == 0) return -1;

    int low = 0;
    int high = nums.length - 1;

    while (low <= high) {
        int mid = low + ((high - low) >> 1);
        if(nums[mid] == target) return mid;

        if(nums[low] <= nums[mid]) {
            if(nums[mid] > target && nums[low] <= target) {
                high = mid - 1;
            } else {
                low = mid + 1;
            }
        } else if(nums[low] > nums[mid]) {
            if(nums[mid] < target && nums[high] >= target) {
                low = mid + 1;
            } else {
                high = mid - 1;
            }
        }
    }

    return -1;
}

来源：CSDN

作者：发霉的宅大人

链接：https://blog.csdn.net/Qinhaifu/article/details/104607722