Spring-Jersey : How to return static content?

Question :

How do I expose my css/, images/, js/ and other static files?
How do I return a JSP page in my controller (not a String method) for my index view?

Problems :

In efforts to solve question #1 other projects use a filter jersey.config.servlet.filter.staticContentRegex (as seen here Stackoverflow Question) I haven't been able to find dependencies that work correctly/at all with my project setup.
In efforts to solve question #2 I attempted to introduce dependencies to use Viewable. Problem - transitive dependencies adversely affect the webapp from using the appropriate classes for Spring & Jersey (snowballs into a rabbit hole of nebulous errors)

Complete Project > Github Project

<dependency>
<groupId>org.glassfish.jersey.containers</groupId>
<artifactId>jersey-container-servlet</artifactId>
<version>2.15</version>
</dependency>
<dependency>
<groupId>org.glassfish.jersey.ext</groupId>
<artifactId>jersey-spring3</artifactId>
<version>2.15</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-web</artifactId>
<version>3.2.3.RELEASE</version>
</dependency>
<dependency>
<groupId>commons-logging</groupId>
<artifactId>commons-logging</artifactId>
<version>1.1</version>
<exclusions>
<exclusion>
<groupId>javax.servlet</groupId>
<artifactId>servlet-api</artifactId>
</exclusion>
</exclusions>
</dependency>

Web.xml > Web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>Jersey</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.component.ResourceRegister</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>

Controller > SpringController.java

@Path("/")
@Component
public class SpringController {

@GET
@Produces(MediaType.TEXT_HTML)
public ?? getIndex() {

    //How do I return my index page??
    return ??
 }
}

Paul Samsotha

"How do I expose my css/, images/, js/ and other static files?"

The jersey.config.servlet.filter.staticContentRegex property should work, but you need to specify all the possible patterns for all the types of files you want to serve. The easier way is to just use the property jersey.config.servlet.filter.forwardOn404, as pointed out in this answer. And yes with both choices, you need configure Jersey as a filter, rather than a servlet. So your web.xml might look like

<filter>
    <filter-name>Jersey</filter-name>
    <filter-class>org.glassfish.jersey.servlet.ServletContainer</filter-class>
    <init-param>
        <param-name>javax.ws.rs.Application</param-name>
        <param-value>com.component.ResourceRegister</param-value>
    </init-param>
    <!-- pass to next filter if Jersey/App returns 404 -->
    <init-param>
        <param-name>jersey.config.servlet.filter.forwardOn404</param-name>
        <param-value>true</param-value>
    </init-param>
</filter>

<filter-mapping>
    <url-pattern>/*</url-pattern>
    <filter-name>Jersey</filter-name>
</filter-mapping>

"How do I return a JSP page in my controller (not a String method) for my index view?"

First thing you need is the jsp mvc dependency

<dependency>
    <groupId>org.glassfish.jersey.ext</groupId>
    <artifactId>jersey-mvc-jsp</artifactId>
    <version>2.25</version>
</dependency>

Then you need to register the feature

public ResourceRegister () {
    ...
    register(JspMvcFeature.class);
}

Then you need to specify the template base path for all your jsp pages. For example I used /WEB-INF/jsp

public ResourceRegister () {
    ...
    property(JspMvcFeature.TEMPLATE_BASE_PATH, "/WEB-INF/jsp");
}

So for this case, all the jsp files should be located in /WEB-INF/jsp directory.

Example jsp and controller

index.jsp

<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
        <title>JSP Page</title>
        <link href="css/styles.css" rel="stylesheet">
    </head>
    <body>
        <h1>${it.hello} ${it.world}</h1>
    </body>
</html>

Controller

@Path("/")
public class HomeController {

    @GET
    @Produces(MediaType.TEXT_HTML)
    public Viewable index() {
        Map<String, String> model = new HashMap<>();
        model.put("hello", "Hello");
        model.put("world", "World");
        return new Viewable("/index", model);
    }
}

public ResourceRegister () {
    ...
    register(HomeController.class);
}

Here the /index in the Viewable points the index.jsp (we don't need the .jsp extension). Jersey knows how to find the file from the property we set above.

See Also:

来源：https://stackoverflow.com/questions/31883928/spring-jersey-how-to-return-static-content

标签

java

Spring

jersey

jersey-2.0

static-content