输入一棵二叉搜索树,将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点,只能调整树中结点指针的指向。
/**
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
*/
///???????????????????????????????
public class Solution {
TreeNode head = null;
TreeNode realHead = null;
public TreeNode Convert(TreeNode pRootOfTree) {
ConvertSub(pRootOfTree);
return realHead;
}
private void ConvertSub(TreeNode pRootOfTree) {
if(pRootOfTree==null) return;
ConvertSub(pRootOfTree.left);
if (head == null) {
head = pRootOfTree;
realHead = pRootOfTree;
} else {
head.right = pRootOfTree;
pRootOfTree.left = head;
head = pRootOfTree;
}
ConvertSub(pRootOfTree.right);
}
}
来源:oschina
链接:https://my.oschina.net/u/4167465/blog/3163120