Detect if a generic type is open?

问题

I have a bunch of regular, closed and opened types in my assembly. I have a query that I'm trying to rule out the open types from it

class Foo { } // a regular type
class Bar<T, U> { } // an open type
class Moo : Bar<int, string> { } // a closed type

var types = Assembly.GetExecutingAssembly().GetTypes().Where(t => ???);
types.Foreach(t => ConsoleWriteLine(t.Name)); // should *not* output "Bar`2"

Upon debugging the generic arguments of an open type, I found that their FullName is null (as well as other things like the DeclaringMethod) - So this could be one way:

    bool IsOpenType(Type type)
    {
        if (!type.IsGenericType)
            return false;
        var args = type.GetGenericArguments();
        return args[0].FullName == null;
    }

    Console.WriteLine(IsOpenType(typeof(Bar<,>)));            // true
    Console.WriteLine(IsOpenType(typeof(Bar<int, string>)));  // false

Is there a built-in way to know if a type is open? if not, is there a better way to do it? Thanks.

回答1:

You could use IsGenericTypeDefinition:

typeof(Bar<,>).IsGenericTypeDefinition // true
typeof(Bar<int, string>).IsGenericTypeDefinition // false

回答2:

Type.IsGenericTypeDefinition is not technically the correct property to rule out open types. It will however work just fine in your case (and indeed in most other cases).

That being said, a type can be open without being a generic type definition. In the more general case, e.g. in a public method that accepts a Type parameter, what you really want is Type.ContainsGenericParameters.

For full details see the answer to this question:
Difference between Type.IsGenericTypeDefinition and Type.ContainsGenericParameters

TL;DR: The latter is recursive, while the former is not, and can thus be "fooled" by constructing a generic type that has a generic type definition as at least one of its generic type parameters.

来源：https://stackoverflow.com/questions/25811514/detect-if-a-generic-type-is-open

标签

reflection

generic-type-argument