C++ cout 按2、8、10、16进制输出

#include <iostream>

#include <bitset>

using std::cout;
using std::endl;

int main(int argc,char *argv[],char *envp[])
{
	cout<<"binary: "<<std::bitset<8>(16)<<endl;//输出八位二进制数16, 00010000
	cout<<std::showbase<<std::oct<<"octal: "<<16<<endl;// 020
	cout<<std::showbase<<std::dec<<"decimal: "<<16<<endl;// 16
	cout<<std::showbase<<std::hex<<"hexdecimal: "<<16<<endl;// 0x10
	return 0;
}

 

来源：CSDN

作者：zing2000

链接：https://blog.csdn.net/zing2008/article/details/104393432