SuperObject - Extract All

问题

How to get ALL 'id' member values from a generic JSON. Without knowing structure of it. Because its very complex and it has a lot of sub objects. It has to loop through all the sub objects.

Again for people that keep on asking where is the example JSON. My question is about how to extract a member value in my case "id" from any generic JSON that has this member inside.

回答1:

If you don't know the structure of the JSON you receive from somewhere, it is important to note that JSON is "simply" a composite pattern and you can traverse it like any other composite structure. The following example traverse the complete structure in a JSON text and prints the path of any member named 'id'.

procedure ParseJSON;
var
  JSONText: string;
  JSON: ISuperObject;
begin
  // Retrieve JSON as a string into JSONText variable any way you like.
  JSON := SO(JSONText);
  ProcessObject(JSON.AsObject);
end;

procedure ProcessObject(const aAsObject: TSuperTableString; const aPrefix: string = '');
var
  Names: ISuperObject;
  Name: string;
  Items: ISuperObject;
  Item: ISuperObject;
  idx: Integer;
  Value: string;
  ArrayItem: ISuperObject;
begin
  if Assigned(aAsObject) then
  begin
    Names := aAsObject.GetNames;
    Items := aAsObject.GetValues;

    for idx := 0 to Items.AsArray.Length - 1 do
    begin
      Name := Names.AsArray[idx].AsString;
      Item := Items.AsArray[idx];
      if Item.DataType = stObject then
        Value := '<Object>'
      else if Item.DataType = stArray then
        Value := '<Array>'
      else
        Value := Item.AsString;

      if SameText(Name, 'id') then
        WriteLn(Format('%s: %s', [aPrefix + Name, Value]));

      if Item.DataType = stArray then
        for ArrayItem in Item do
          ProcessObject(ArrayItem.AsObject, aPrefix + Name + '.');

      if Item.DataType = stObject then
        ProcessObject(Item.AsObject, aPrefix + Name + '.');
    end;
  end;
end;

来源：https://stackoverflow.com/questions/14082886/superobject-extract-all