问题
I looked but i didn't found the answer (and I'm pretty new to python).
The question is pretty simple. I have a list made of sublists:
ll
[[1,2,3], [4,5,6], [7,8,9]]
What I'm trying to do is to create a dictionary that has as key the first element of each sublist and as values the values of the coorresponding sublists, like:
d = {1:[2,3], 4:[5,6], 7:[8,9]}
How can I do that?
回答1:
Using dict comprehension :
{words[0]:words[1:] for words in lst}
output:
{1: [2, 3], 4: [5, 6], 7: [8, 9]}
回答2:
Using dictionary comprehension (For Python 2.7 +) and slicing -
d = {e[0] : e[1:] for e in ll}
Demo -
>>> ll = [[1,2,3], [4,5,6], [7,8,9]]
>>> d = {e[0] : e[1:] for e in ll}
>>> d
{1: [2, 3], 4: [5, 6], 7: [8, 9]}
回答3:
you could do it this way:
ll = [[1,2,3], [4,5,6], [7,8,9]]
dct = dict( (item[0], item[1:]) for item in ll)
# or even: dct = { item[0]: item[1:] for item in ll }
print(dct)
# {1: [2, 3], 4: [5, 6], 7: [8, 9]}
回答4:
Another variation on the theme:
d = {e.pop(0): e for e in ll}
来源:https://stackoverflow.com/questions/32604558/get-first-element-of-sublist-as-dictionary-key-in-python