问题
It keeps concatenating my numbers into 2111 instead of 5. Why is this? I've tried using parseInt with no luck. res3 btw represents a query into my database that I'm executing.
var dt_total_hours = 0;
dt_total_hours += res3.fieldByName(dt_cost_per_hour);
dt_total_hours += res3.fieldByName(dt_prod_dt_hours);
dt_total_hours += res3.fieldByName(dt_prod_rate);
dt_total_hours += res3.fieldByName(dt_cost_per_unit);
dt_total_hours += res3.fieldByName(dt_scrap_startup_cost);
dt_total_hours += res3.fieldByName(dt_labor_expense);
dt_total_hours += res3.fieldByName(dt_since_issues_first_noticed);
dt_total_hours += res3.fieldByName(dt_wo_for_maint);
dt_total_hours += res3.fieldByName(dt_investigation);
dt_total_hours += res3.fieldByName(dt_maint_made_bandaid);
dt_total_hours += res3.fieldByName(dt_parts_outsourcing);
dt_total_hours += res3.fieldByName(dt_get_equip_out_prod);
dt_total_hours += res3.fieldByName(dt_perm_repair);
dt_total_hours += res3.fieldByName(dt_equip_back_to_prod);
dt_total_hours += res3.fieldByName(dt_to_full_prod_speed);
dt_total_hours += res3.fieldByName(dt_other);
回答1:
If the values are strings then they will be concatenated, not added numerically.
Try constructing a number from the string value:
dt_total_hours += Number(res3.fieldByName(dt_cost_per_hour));
// ^------ Force a number here instead of a string.
回答2:
Yeah, it's reading them as strings. I find that a dirty, awful hack to get them interpreted as numbers is to take x += y
and change it to x += y / 1.0
(or / 1
for integer). Usually does the trick.
回答3:
you can parse your data according to desired type as follow
dt_total_hours += parseInt(res3.fieldByName(dt_cost_per_hour));
you can also use parseFloat method as well
来源:https://stackoverflow.com/questions/14656003/javascript-concatenating-numbers-not-adding-up