问题
I have a simple Scala project that looks like this...
@Configuration
public class CommonConfiguration{
...
@Value("${spring.kafka.topic}")
public String topic;
...
}
@Service
class KafkaService @Autowired()(producer: KafkaTemplate[String, Array[Byte]], config: CommonConfiguration){
def sendMessage(msg: String): Unit = {
println(s"Writing the message $msg ${config.topic}")
producer.send(config.topic, msg.getBytes());
}
@KafkaListener(id="test", topics="#{'${spring.kafka.topic}'.split(',')}")
def consume(record: ConsumerRecord[String, String]): Unit = {
System.out.println(s"Consumed Strinsg Message : ${record.value()}")
}
}
This gives me the error...
KafkaService.scala:26: error: type mismatch;
[ERROR] found : String("#{\'${spring.kafka.topic}\'.split(\',\')}")
[ERROR] required: Array[String]
[ERROR] @KafkaListener(id="test", topics= "#{'${spring.kafka.topic}'.split(',')}")
I tried using #{'${spring.kafka.topic}'.split(',')}
per this suggestion but I can't get it to work. The producer gets the topic just fine. How do I use Spring Expression Language with Scala?
Here is the working Java Version...
@Service
public class KafkaJavaService {
@KafkaListener(id="test", topics="#{'${spring.kafka.topic}'.split(',')}")
public void consume(ConsumerRecord<String, String> record){
System.out.println("Consumed String Message : "+record.value())
}
}
回答1:
According to this question, it looks like topics = Array("...")
should work.
Reading the
@RequestMapping
documentation : http://static.springsource.org/spring/docs/2.5.x/api/org/springframework/web/bind/annotation/RequestMapping.htmlIt accepts a String array parameter for its path mapping.
So this works using java :
@RequestMapping("MYVIEW")
but in scala I need to use :
@RequestMapping(Array("MYVIEW"))
The scala version makes sense as the annotation expects a String array. But why does above work in java, should it not give a compile time error ?
EDIT
This is also not technically the same thing because the other way I could use a CSV. Even if the worked it would be a 1 string array unless the Array constructor does some fancyness.
It shouldn't make a difference; as I said, if an expression in an element of the String[]
resolves to a String[]
, we recursively break it apart (flatten it). See here and here.
Try setting a breakpoint in those methods; I don't have Scala installed otherwise I'd take a look.
来源:https://stackoverflow.com/questions/60065408/how-do-i-use-spring-expression-language-for-an-array-in-an-annotation-with-scala